Math Is Fun Forum

I've only played the First Person Shooters for it (which seems to be pretty the only kind of games on the 360 to be honest) Gears of War and Halo 3 were ok, but I get bored of FPS really quick. I hear good things about Assassin's Creed.

It's a bit tough to do it in one try. There are SO many different kinds of relationships. Just to name a few, you have Linear, Logarithmic, Polynomial, and Exponential.

One of the easiest ways (in method and accessibility) is to put the two columns into Excel and graph them. Line is normally the best unless you have multiple results for the same numbers. Make sure you sort them with the input values going from lowest to highest first! Just look at the graph and see if there's any visible relationship.

I can tell you that I've done this with the data you provided and it looks pretty random, but try it for yourself and see what you think.

Mail comes in the door,
pre-approved for a credit card.
Mail goes in the trash.

Yep. Well done, Ganesh.

I was never happy with the supposedly philosophical question "Is the glass half empty or half full?".

It depends on the context really. If the process of filling the glass gets it to that point, then it's half full. If you empty the water from the glass to get to that point, then it's half empty. If the glass just suddenly existed with half it's potential volume of water in it, then I think the better question is "Where did it come from and why is it here?"

Guess 1: 314 1C1B
Guess 2: 897 1C

Thanks, Luca. I thought that was right, but wasn't sure. I knew there weren't any real answers, though

Can you double check the output you gave? I'm assuming that the words are alpha only with upper and lower case. Examples I've tried
so far seem to all produce a 3 digit number for each letter either beginning with 1 or 2. The length of the output you've given isn't
divisible by three.
If I'm right, then I believe there is a method, but it does involve brute force (of a kind). It appears initially that for any given string length
each letter corresponds to a specific number depending upon it's position regardless of the other letters around it. I'd basically have to
calculate a massive lookup table.
Assuming I can deduce the length of the string by len(string)/3, then I can use the lookup table to deduce the values for each 3-digit number.

This is all dependant on the fact that the number you gave is missing a digit or two, though

No, it's fine the way you've done it.
A major step in deciphering it would be to know the total length of the three strings. Even if you were able to deduce that somehow
you'd still be unable to determine what part of the concatenated string is Password0, Password1, and UserName. I thought there was
a clue in the encoding string, but that was before I realised all three strings went into the same variable.

Yes, that's true and I see I forgot to mention why he can't have that label. I'm very sorry about that.

If he did have the Three Blues label, then when we come to Math, his only choices for a label that tell him what he has are One Blue or Two Blues. (No Blues would be useless because he already has one blue!)

If he has the One Blue label, then that would mean he has two blue marbles (but Tom already has two, so he can't!).
So he must have the Two Blues label and has 1 blue marble.

Now Harry goes and gets his two yellows. The only remaining labels are "One Blue" and "No Blues". Either way he would be able to tell what he had in his jar, but the problem says that he didn't know, so that can't be right.

Sounds like a bass with guitar strings.

The puzzle starts out saying that there are 4 jars.
We're then told that each jar contains 3 marbles made up of blue and yellow.
Also, the number of blue marbles in each one is different.

We can make some assumptions at this point. For three marbles, there are only 4 different amounts of blue that you can have; 0, 1, 2, and 3.
So somebody has no blue marbles, someone has 1, someone has 2, and someone has 3.

We're now told that there's a label in each that describes the number of marbles incorrectly.
So somebody has a label which says "No blue marbles", "1 Blue Marble", etc

Tom takes out two blues and reads his label and knows the answer immediately. He has the "Two Blue Marbles" label because (if it is indeed wrong) that means that the remaining marble can't be Yellow; it must be blue. Since he was the first to go, this is the ONLY label that allows him to know for certain what he has.
So Tom has 3 Blues and the "Two Blue Marbles" label.

Math takes out a Blue and a Yellow and once again know immediately. The only options for him are two blue marbles or one blue marble. He would then either have the "Two Blue Marbles" label or the "One Blue Marble" label. Since Tom has "Two Blue Marbles", then Math must have "One Blue Marble". Since the label is wrong, it must mean that Math has two blue marbles.
So Math has 2 Blues and the "One Blue Marble" label.

Harry now gets two yellows, but he can't tell what the last one is. The only labels remaining are "Three Blue Marbles" or "No Blue Marbles". If he had the "No Blue Marbles" label, then he would know the last one is a Blue marble, because all the labels are wrong. He must therefore have the "Three Blue Marbles" label.
So Harry has either 0 or 1 blue marbles and the "Three Blue Marbles" label.

Sally doesn't even bother to look. Tom and Math have the 3 and 2 marbles so like Harry she can only have 0 or 1. The only label remaining is "No Blue Marbles", which she would know from seeing the other labels. Since the labels are wrong, then she must have 1 marble.
So Harry has 0 marbles and the "Three Blue Marbles" label.
And Sally has 1 marble and the "No Blue Marbles" label.

Hope that helps?