Math Is Fun Forum

Why did the chicken cross the Moebius strip?

To get to the other side... wait, no, that wasn't it....:)

Determined? yes, I agree; known? Not at all. At least not after n number of decimal places. I'm not, however, saying that this is a valid counter-arguement, because I don't subscribe to the thinking of if we can't disprove it, it must exist. I will however still believe that in the higher decimal places if pi, its digits become a faith, in a sense. What I mean is that after n digits, we have to accept the fact that there is still an inifinite number of digits left. So, with that said, probability could very well be involved in pi, in that the division could take a turn for one million continuous zeros.

Now, I'm quite the amateur, so correct me when I veer off the mathematician's path here, as I most likely will do. If pi is non-repeating, non-terminating, then as many digits of pi that you can calculate is only equal to ∞-n/∞ of its digits, right? So, if we looked at pi and said, "Well, it cannot contain one million zeros. And look, we've calculated it one billion places, and no zero or string of numbers 0 through 9." Then aren't we haunted by the fact that this is only ∞-n/∞ of its digits, and the fact that there are infinite numbers left. So, even if we calculated it to some astronomically high digit place and found nothing, we'd have to calculate even more, and more, and more, forever. Well, interestingly enough, I would think that the probability of 14159265358979 is equal to 111..., or 222.... However, if we accept the fact that it is infinite, then however counter-intuitive it seems, doesn't the same probability go for a million zeroes? This is only my unprofessional opinion. But it would be interesting to discuss.

However, my friend, another armchair mathematician, brought up an interesting point. He said that if pi is a division problem, such as circumference divided by diameter, then in order for it to contain one million continuous zeros, pi would have to be terminating, or at least repeating, in that to contain one million zeros, circumference/diameter = 3.14 ...000..., which means it couldn't possibly jump back to 1, right?

Either way, I think it's another interesting point.

Welcome, relax4now.

Zdravstvuite, Umbros. I'm sure you'll like it here.

Oh, yes. They're all disgusting. And the noise the fly makes is terribly frightening to me. Have you ever thought of how sinister that sounds? That buzz? That drives me insane.

And by 11
as in 25 x 11 =
take the first digit, which is 2 and write it down. Then add the first digit to the second digit, which is 2 + 5, which equals 7, so that now we have 2 & 7. Finally, take the last digit, which is 5, and write it down. So, 25 x 11 = 275
The good thing is that this method works for any number times 11, like 1,450,623. Just repeat the second step until you've done all the digits. So, 11 x 1,450,623 = 15,956,853

Well, if you're allowed to use mathsyperson's technique, then 1/number of fractions that sum up to 1 would be your technique. So for 8 sets of fractions, it's just 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 + 1/8 = 1

Of course the reason this works is simply that if seven fractions sum up to 1, then the denominator is 1/7 of 1.

All right. Sorry, JohnnyReinB, I didn't know how to use the hidetags. Thanks.
So, i'll re-type my answers and delete my last post.