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#1 Re: Help Me ! » Differentiation help needed! » 2012-04-18 23:03:58

Ah! I get it now. Thanks, I didn't realize that (2+h,(2+h)^2+5(2+h)) was a coordinate.

#2 Help Me ! » Differentiation help needed! » 2012-04-18 02:31:51

Marisca
Replies: 4

Hi, I'm having trouble with this question.

For a curve with equation y=x^2+5x
a) find the gradient of the chord PQ where P is the point (2.14) and Q is the point (2+h,(2+h)^2+5(2+h)).

#4 Re: Help Me ! » Linear literal equations » 2012-04-06 21:51:01

hi bobbym, the question was asking for a parameter.

Thanks, that really helped smile

#5 Re: Help Me ! » Linear literal equations » 2012-04-04 15:52:54

Ok, I have another question.

x-y = 6 and 2x-2y=12 have infinitely many solutions. Describe these solutions through the use of a parameter.

All I've been able to do so far is set up the matrices, but I don't know where to go from there.

#7 Re: Help Me ! » Linear literal equations » 2012-04-04 13:04:50

ok, so I'm not sure if this is right, but I got

x=-ab/(b-1)

also, why did you multiply by x(x+1)?

#8 Help Me ! » Linear literal equations » 2012-04-04 12:40:22

Marisca
Replies: 12

Hi, I'm having trouble solving for x with this question

1/(x+a) = b/x

#9 Re: Help Me ! » Help needed! » 2012-03-31 11:35:26

ah, thanks everyone!!
I definitely understand it now. smile

#10 Help Me ! » Help needed! » 2012-03-30 22:50:12

Marisca
Replies: 9

Hi, I can't seem to solve this problem;

Factor f(x)=6x^3+5x^2-17x-6 completely.

#11 Re: Help Me ! » Exponential help needed! » 2012-03-26 00:31:12

Thank you! I understand it now.

#12 Re: Help Me ! » Exponential help needed! » 2012-03-25 01:56:53

So something like y=0?

Also, would I need to sub f(x)=2^x into y=f(x+1)?

#13 Help Me ! » Exponential help needed! » 2012-03-25 00:27:05

Marisca
Replies: 5

Hi, I have a question that I don't really understand.

For f(x)=2^x, sketch the graph of the following, labeling asymptotes where appropriate:
a) y=f(x+1)

#14 Re: Help Me ! » Families of functions help needed! » 2012-03-12 03:35:56

Yes, I could finish it from there.
Thanks a lot, really helped me smile

#15 Help Me ! » Families of functions help needed! » 2012-03-10 14:20:11

Marisca
Replies: 3

Find {x:x^3/2 > x^2}

I Have no idea how to do this, please help!

#17 Re: Help Me ! » Unique, infinite and no solutions... » 2012-01-14 02:09:39

Thanks, but I don't understand how you arrived at those answers.

#18 Help Me ! » Unique, infinite and no solutions... » 2012-01-14 01:38:09

Marisca
Replies: 7

Hi, could anyone help me with this problem?

Find the values of b and c, or the relationship  between b and c, for which the equations
x+5y=4 and 2x+by=c have:
I) a unique solution,
II) an infinite set of equations,
III) no solution.

#19 Re: Help Me ! » Implied Domain » 2012-01-10 18:30:22

Alright, thanks a lot smile
Oh, and that video is really helpful too!

#20 Help Me ! » Implied Domain » 2012-01-10 12:57:49

Marisca
Replies: 4

Hi again, I'm stuck on this equation, 

Untitled-3.jpg

I'm really not sure how I'm supposed to approach it.

#22 Help Me ! » Need help with expanding... » 2012-01-09 18:25:38

Marisca
Replies: 3

Hi,
For f(x)=3x^2+x-2 find: {x:f(x)>0}

for this question I expanded and got;

(3x-2)(x+1)>0, and from that x>2/3 and x>-1, which turns out as incorrect.

Could someone tell me where I went wrong?

#23 Re: Help Me ! » Linear functions and Matrices » 2011-10-07 00:16:50

Yes I think so. It's probably not likely that they're going to sneak it into my exam.
Thanks for your help.

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