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Ah! I get it now. Thanks, I didn't realize that (2+h,(2+h)^2+5(2+h)) was a coordinate.
Hi, I'm having trouble with this question.
For a curve with equation y=x^2+5x
a) find the gradient of the chord PQ where P is the point (2.14) and Q is the point (2+h,(2+h)^2+5(2+h)).
Ok, thank you
hi bobbym, the question was asking for a parameter.
Thanks, that really helped
Ok, I have another question.
x-y = 6 and 2x-2y=12 have infinitely many solutions. Describe these solutions through the use of a parameter.
All I've been able to do so far is set up the matrices, but I don't know where to go from there.
Ok, thanks!
ok, so I'm not sure if this is right, but I got
x=-ab/(b-1)
also, why did you multiply by x(x+1)?
Hi, I'm having trouble solving for x with this question
1/(x+a) = b/x
ah, thanks everyone!!
I definitely understand it now.
Hi, I can't seem to solve this problem;
Factor f(x)=6x^3+5x^2-17x-6 completely.
Thank you! I understand it now.
So something like y=0?
Also, would I need to sub f(x)=2^x into y=f(x+1)?
Hi, I have a question that I don't really understand.
For f(x)=2^x, sketch the graph of the following, labeling asymptotes where appropriate:
a) y=f(x+1)
Yes, I could finish it from there.
Thanks a lot, really helped me
Find {x:x^3/2 > x^2}
I Have no idea how to do this, please help!
Thanks.
Thanks, but I don't understand how you arrived at those answers.
Hi, could anyone help me with this problem?
Find the values of b and c, or the relationship between b and c, for which the equations
x+5y=4 and 2x+by=c have:
I) a unique solution,
II) an infinite set of equations,
III) no solution.
Alright, thanks a lot
Oh, and that video is really helpful too!
Hi again, I'm stuck on this equation,
I'm really not sure how I'm supposed to approach it.
Thank you!
Hi,
For f(x)=3x^2+x-2 find: {x:f(x)>0}
for this question I expanded and got;
(3x-2)(x+1)>0, and from that x>2/3 and x>-1, which turns out as incorrect.
Could someone tell me where I went wrong?
Yes I think so. It's probably not likely that they're going to sneak it into my exam.
Thanks for your help.
Thanks for the tip
Z=1/(a-3)