Exponential help needed!

Marisca · 2012-03-25 00:27:05

Hi, I have a question that I don't really understand.

For f(x)=2^x, sketch the graph of the following, labeling asymptotes where appropriate:
a) y=f(x+1)

bobbym · 2012-03-25 01:06:54

Hi Marisca;

Start here:

Graph your function over here:

Can you visually identify a possible horizontal asymptote?

Marisca · 2012-03-25 01:56:53

So something like y=0?

Also, would I need to sub f(x)=2^x into y=f(x+1)?

bobbym · 2012-03-25 02:07:45

Hi Marisca;

Exactly y = 0.

Also, would I need to sub f(x)=2^x into y=f(x+1)

If f(x) = 2^x then f(x+1) = 2^(x+1) wherever you see an x you substitute x + 1.

The equation y = f(x+1) is y = 2^(x+1)

Marisca · 2012-03-26 00:31:12

Thank you! I understand it now.

bobbym · 2012-03-26 00:34:43

Hi;

Wunderbar! Glad to help!

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