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I'm not sure how I would do that on my calculator b/c it's a hp 9g graphing calculator. Is there another way to simplify it more to get the answer?
My book says the answer is 0.466
I get x^3+2x^2+x-1 right? And then what?
use the fact:
I can get to that part but I don't know what to do after that.
I need help with figuring out how to solve these two problems.
1: logbase7(1-x)-logbase7(x+2)=logbase7x^2
2: logbase3(2-x)-logbase3(x+3)=logbase3x
Thank you.
I was trying to solve the one you put before and you edit it out? Why do you do that? I dont feel like wasting my own time to help you and then you edit it out.
Good luck.
Sorry. It was the wrong problem that I needed help with.
Ok. Thanks!
Do you know how I would set up this equation to solve it?
lN(INx) = 1
The only way that I got 2.177 was putting in parenthesis around only SQRT ((In42) + 1) and I got the answer from the book.
What answer did you get? The book says +- 2.177
Nevermind
Thank You!!
- - 13 PlusOrMinusForTwoAnswers SquareRootOF[13^2 - 4(6)(6 - 10^(3/2)] all over 2(6) = x
+13 PlusOrMinus SquareRootOf{169 - (4)(6)(6) - - (4)(6)(10^[3/2])} all over 12 = x
13 PlusOrMinus SquareRootOf{169 - (4)(36) + (24)(10^[3/2])} all over 12 = x
13 PlusOr Minus SquareRootOf{169 - (2)(72) + (24)(1000^[1/2])} all over 12 = x
24 times 24 is 576, which is (3)(2)(2)(2) squared, oh forget that, put it in and back out of 1000 doesn't help.
1000 is (5)(2)(5)(2)(5)(2), so two 5's and and two 2's can come out of the 1000^(1/2).
1000^(1/2) = (5)(2) [(5)(2)]^{1/2} => 10 squareRoot(10)
13 PlusOrMinus SquareRootOf{169 - (2)(72) + (24)(10)(10^[1/2])} all over 12 = x
2 times 72 = 144, 169 - 144 is 25.
13 PlusOrMinus SquareRootOf{25 + 240(10^[1/2])} all over 12 = x
I don't know how to simplify it anymore, but if
you just use your calculator, you can get an
approximation.x = -1.249920592 the Right Answer because I plugged it back in.
.759649851 + .740350148 = 1.5
The other answer of x = 3.416587258 is WRONG because if you plug it into original problem,
it goes negative inside the logarithms.
logbase7(1-x) - logbase7(x+2) = logbase7(x^2)
logbase7((1-x)/(x+2)) = logbase7(x^2)
(1-x)/(x+2) = x^2
x^3 + 2x^2 + x - 1 = 0
x = 0.465571231877
How do I find x?
I need help trying to figure out how to solve these step by step please
log (2-3x) + log (3-2x) = 1.5
logbase7(1-x) - logbase7(x+2) = logbase7(x^2)
Thank You!
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