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I need help with figuring out how to solve these two problems.
1: logbase7(1-x)-logbase7(x+2)=logbase7x^2
2: logbase3(2-x)-logbase3(x+3)=logbase3x
Thank you.
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use the fact:
Last edited by Kurre (2008-04-19 02:22:08)
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use the fact:
I can get to that part but I don't know what to do after that.
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From here it should be straightforward to solve.
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I get x^3+2x^2+x-1 right? And then what?
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Solve.
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1.)
Woops, this is wrong, the decimal point was off by one, sorry.
x = 0.19199398 approximately says BASIC program.
Last edited by John E. Franklin (2008-04-19 06:46:53)
igloo myrtilles fourmis
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my TI-89 says x=1.75487766625 as the answer for the polynomial.
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My book says the answer is 0.466
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@Luis and Daniel, there is a -/+ mixup in Daniels post.
igloo myrtilles fourmis
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1.) 0.46557123 is more accurate, BASIC program.
2.) 0.4494897
Last edited by John E. Franklin (2008-04-19 07:01:29)
igloo myrtilles fourmis
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Oh thanks for pointing that out. I just took Daniel's answer for granted. So:
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I'm not sure how I would do that on my calculator b/c it's a hp 9g graphing calculator. Is there another way to simplify it more to get the answer?
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Does your calculator have a "solve" function as the TI-89 does?
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1.) 0.4655712318767681 according to a cubic solving applet on web.
http://tunesmithy.netfirms.com/japplets/iterative_solution_of_cubic.htm
Last edited by John E. Franklin (2008-04-19 07:05:05)
igloo myrtilles fourmis
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Franklin, is there any method to solve this polynomials of 3 degrees and higher?
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@Luis and Daniel, there is a -/+ mixup in Daniels post.
Woops. Sorry everyone.
I'm not sure how I would do that on my calculator b/c it's a hp 9g graphing calculator. Is there another way to simplify it more to get the answer?
You could use a manual numerical method if your calculator can't do it itself.
Rearrange to give:
This gives us the iterative formula:
You can see that substituting -1 into the orginal equation gives a negative answer, and substituting 1 gives a positive answer. You therefore know that a root must lie in that interval, as the function is continuous (so it must cross the x-axis in order to go from positive to negative). Pick a value in between, such as 0, and substitute it into the formula (i.e use
). Then keep substituting the value it gives out back into your calculator.The quickest way to do this is press '0 =' on your calculator. Then type
and keep pressing equals until the answer converges to as many decimal places as you need.This is just one of many numerical methods you could use, but it is probably the easiest.
Last edited by Daniel123 (2008-04-19 08:18:54)
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Wow, Daniels is smart. You can do square roots like that, but
I forget how. I was reading on solving a cubic equation a month ago, but it was so hard I left it on the back burner for now.
igloo myrtilles fourmis
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Yeah, I tried to read one of those a while ago. All I remember is that you need to make some kind of substitution that transforms a general cubic equation into one of the form ax³ + bx + c (ie. no quadratic term).
It's easier to solve that than a general cubic, and then you can reverse the substitution to get the original answer. Unfortunately, the method for solving that slightly more specific cubic is still horrendous compared to solving quadratics.
Why did the vector cross the road?
It wanted to be normal.
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hi
I have question about logarithm i am little confused the difference between when used logarithm and when i used natural log
plz give me practical example
your's muhammad
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Does your calculator have a "solve" function as the TI-89 does?
log x=-3/2
log 3=x
log 1/4=x
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