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what if it was just
5y= logx^5
would it be possible in this case to take the log of 5y and do the same workings as before?
how do i make make x the subject in this equation?
log5y= logx^5
thanks
when a question asks: simplify the following
1. a) √12
b) √112
is the answer simply the square root of these numbers?
then
2. express the following in the form (a√c) / b , where a b and c are all integrers
a) (3√11) / (2√3)
b) (5√6) / √7
how do i go about doing this?
appreciate the help, thankyou
thankyou very much
please help me
write down the values of each of the following:
a) (27/125) ^ -2/3
b) 32^3/5
could you please show you working too?
thankyou very very much!!
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