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#1 2008-05-31 04:51:50
- lucinda01
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- Registered: 2008-05-29
- Posts: 3
log solving
how do i make make x the subject in this equation?
log5y= logx^5
thanks
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#2 2008-05-31 07:18:27
- amish
- Member
- Registered: 2008-04-02
- Posts: 10
Re: log solving
Ok heres how I did it
I'm not sure if i'm right though, so if someone could check through. Thanks.
~Amish
Last edited by amish (2008-05-31 07:29:54)
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#3 2008-05-31 18:59:50
- luca-deltodesco
- Member
- Registered: 2006-05-05
- Posts: 1,470
Re: log solving
your identity is incorrect 
.
or; better applicable here
hence.
Last edited by luca-deltodesco (2008-05-31 19:02:59)
The Beginning Of All Things To End.
The End Of All Things To Come.
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#4 2008-06-01 01:54:35
- lucinda01
- Member
- Registered: 2008-05-29
- Posts: 3
Re: log solving
what if it was just
5y= logx^5
would it be possible in this case to take the log of 5y and do the same workings as before?
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#5 2008-06-01 04:50:12
- luca-deltodesco
- Member
- Registered: 2006-05-05
- Posts: 1,470
Re: log solving
no, you'd still take the exponential of both sides, and you'd end up with
Last edited by luca-deltodesco (2008-06-01 04:50:58)
The Beginning Of All Things To End.
The End Of All Things To Come.
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