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#1 Re: Help Me ! » I'm not sure why but I dreamed about this equation » 2013-12-08 20:33:39

oh ya right.......exactly....
e^(i*pi)=cos(pi)+i sin(pi)....
why didn't i think of this before....
thank you bob....

#2 Re: Help Me ! » I'm not sure why but I dreamed about this equation » 2013-12-08 19:53:33

Hello anonimnstefy....
how did someone end up with such an equality??
I mean i've tried it many times but i never got that equation right........
I could never compute e^i......
And can anyone put some sense into that equation....

#3 Re: Help Me ! » I'm not sure why but I dreamed about this equation » 2013-12-07 01:31:19

And just as dford i'm stuck with
e^(i*pi)+1=0.......
Does anyone know what is that supposed to mean........???

#4 Re: Help Me ! » I'm not sure why but I dreamed about this equation » 2013-12-07 01:28:55

Hello everyone
why would anyone use such constant upto 14 decimal places........??
And what is that series called....??

#5 Re: Dark Discussions at Cafe Infinity » [1 paradox] » 2013-04-07 22:11:57

Hello Bob;
Guess that approximation can be done.......

#6 Re: Dark Discussions at Cafe Infinity » [1 paradox] » 2013-04-06 19:12:30

Hello Bob;
'm good and how are you doing.....???

and those aren't two numbers in actual sense .........
because pi is a symbol that is used to represent a particular decimal,3.1415.........

Hello Bobbym;
almost the whole of the argument you were trying to prove that .999999...... isn't equal to unity
that is what i actually agreed on..........

#7 Re: Dark Discussions at Cafe Infinity » [1 paradox] » 2013-04-05 23:28:48

Hello guys;
i totally agree with Bobbym...
since infinity is no real number and since its value is not known,arithmetic of infinity cannot be performed as we do in case of other numbers.....

And 0.9999999999999.....can never be equal to unity.....
limit of .999999..... could be 1
but saying that .99999999...itself is equal to 1 would be absurd since both of those numbers have their own existence which cannot be equated......

#9 Re: Help Me ! » centroids » 2012-12-29 20:41:44

ya for that curve CB.......
i arrived at the same answer even when i did i for the whole curve so,i just clarified .....
anyway thank you for your help BOB............:):D

#10 Re: Help Me ! » centroids » 2012-12-29 20:36:31

Hello bob;
sorry about that -ve sign question .............
now that i worked out i found it myself.........

#11 Re: Help Me ! » centroids » 2012-12-29 03:41:02

'm wondering why can't one directly find the moment of curve CB.........
finally we need the centroid of the whole of boomerang ..........
bout here centroid of only half of the boomerang is found ......
so how come.....??

#12 Re: Help Me ! » centroids » 2012-12-29 03:36:09

and how's that equal to (200^3)/3-((200^2-100^2)^3/2)/3......???
i mean what happens to the -ve sign with the term (200^3)/3..........??

#13 Re: Help Me ! » centroids » 2012-12-28 01:33:45

actually the problem's with CD and DB..............
I could not understand how you obtained the moments for components CD and DB........

#14 Re: Help Me ! » centroids » 2012-12-28 01:28:28

Hello Bob;
i know the method of moments........
but 'm asking why[and how ] is the integration done for the components present there.............???

#15 Re: Help Me ! » centroids » 2012-12-28 00:00:45

Hello Bob ..........
That's not what i actually meant...........
but anyway can explain that post #24......
in what method is the centroid found there........

#16 Re: Help Me ! » centroids » 2012-12-26 23:39:16

sorry but i have another doubt.....
how is the required area obtained of that rectangle considered...........??

#17 Re: Help Me ! » centroids » 2012-12-26 23:02:43

Hello bob;
sorry for the last post ......
i worked out a bit on it and i figured the step myself so.....

#18 Re: Help Me ! » centroids » 2012-12-26 04:00:42

yes i know that
but 'm referring to the part after substitution of x=200cos u....

#19 Re: Help Me ! » centroids » 2012-12-26 03:05:15

hello bob;
I was actually wondering what happens to the square root in post #15...........?

#20 Re: Help Me ! » centroids » 2012-12-20 23:16:24

hello bob;
its a quarter circle,yes......
but how is it a rectangle..........

#21 Re: Help Me ! » centroids » 2012-12-20 03:29:46

hello bob;
can you please complete it.........
'm completely lost...........

#22 Re: Help Me ! » centroids » 2012-12-19 02:50:32

Hello bob;
how'd u find the co-ordinates of the point "B".......

#23 Re: Help Me ! » centroids » 2012-12-13 01:22:43

hello bob;
i've never seen that before....
can u be more precise...............

#24 Re: Help Me ! » centroids » 2012-12-12 23:02:41

Hello bob;
sorry but 'm wondering how'd u get that equation for curve CA..........???:odunno

#25 Re: Help Me ! » centroids » 2012-12-11 00:51:17

hi bob;
its okay if its its in regular text
later you can post in latex....

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