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Hi bobby, got it, will try it in excel. thx. But still thinking what was wrong in my previous method.
Thanks
Hi anonimnystefy,
taking (y-y1) = m (x-x1) (m is slope)
for L1 : (y-0) = -7/5 (x-512)......A co-ordinates (512,0)
y = -7/5 x + 3584/5 ......
L2 : (y-0) = 2/6 (x-505).........C co-ordinates (505,0)
y = 2/6 x - 1010/6 .........
am I wrong ?
Hi,
I am making a mistake while solving for intersection points of 2 lines :
There is Line L1 from A(512,0) to B(505,5). Another line L2 from C(505,0) to D(507,6)
So, Slope for, L1 = -7/5, L2 = 2/6
To get their intersection points i solve their equations :
Eq. L1 : y = -7/5x + 3584/5 (with point A)
Eq. L2 : y = 2/6 x - 1010/6 (with point C)
So, solving eq. gives me :
-7/5x + 3584/5 = 2/6 x - 1010/6
-42 x + 21504 = 10 x - 5050
52 x = 26554
x = 510.6
But, this is wrong answer (intersection point has to be between 505-507). I dont understand, where i am going wrong. I will be using the suggested method in Excel for futher calculations.
Thanks,
No Smart.
Hi, anonimnystefy, bob, ganesh, bobby, thx all for warm welcome.
Hi all,
I am new to this forum and would like to introduce myself. My name is Raj & I am from India. Hope to share and learn from here.
Thanks,
Raj.
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