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Hi,
I am making a mistake while solving for intersection points of 2 lines :
There is Line L1 from A(512,0) to B(505,5). Another line L2 from C(505,0) to D(507,6)
So, Slope for, L1 = -7/5, L2 = 2/6
To get their intersection points i solve their equations :
Eq. L1 : y = -7/5x + 3584/5 (with point A)
Eq. L2 : y = 2/6 x - 1010/6 (with point C)
So, solving eq. gives me :
-7/5x + 3584/5 = 2/6 x - 1010/6
-42 x + 21504 = 10 x - 5050
52 x = 26554
x = 510.6
But, this is wrong answer (intersection point has to be between 505-507). I dont understand, where i am going wrong. I will be using the suggested method in Excel for futher calculations.
Thanks,
No Smart.
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Hi No_Smart;
Your equations are not correct. I use the pointpoint formula.
Plugging in the points:
I am getting:
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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Your line equations aren't correct. How did you get 3584/5 and -1010/6 ?
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Hi anonimnystefy,
taking (y-y1) = m (x-x1) (m is slope)
for L1 : (y-0) = -7/5 (x-512)......A co-ordinates (512,0)
y = -7/5 x + 3584/5 ......
L2 : (y-0) = 2/6 (x-505).........C co-ordinates (505,0)
y = 2/6 x - 1010/6 .........
am I wrong ?
Last edited by No_Smart (2012-06-24 05:02:53)
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Hi bobby, got it, will try it in excel. thx. But still thinking what was wrong in my previous method.
Thanks
Last edited by No_Smart (2012-06-24 05:05:04)
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Hi;
Try to be a bit more careful and it will work out fine.
for L1 : (y-0) = -7/5 (x-512)......A co-ordinates (512,0)
You figured the slope wrong. It is -5 / 7.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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