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Thanks
How about from the RHS:
RHS=Sin^2xSin^2xSec^x
(1-Cos^2x)Sin^2x(1/Cos^2x)
(Sin^2x/Cos^2x)-(Cos^2xSin^2x/Cos^2x)
Tan^2x-Sin^2x
Correct?
I Used the RHS because I still didn't manage from the LHS.
I'm Stuck on this one:
tan^2x-sin^2x ≡ sin^4x*sec^2x
Need some help
Thanks all!
Here is the link to the picture http://prntscr.com/5in3ie
If log (base y) x = a and log (base z) x = b where x ≠ 1 , express the following in terms of a and b
a) log (base y) yz
b) log (base x) y/z
If y + z =1 show that 1/a = log (base x) 1-x^1/b
I found this hard, if question is unclear and can take a picture of it.
Also bob with your reasoning you helped me solve an even harder question thanks in advance. I'm guessing you helped me find the way
I got it, thanks and yes its does = to 0.
If the expressions x^2+ax+b and 3x^2 +b have (x-c) as a common factor, where a, b and c are non zero show that 3a^2 + 4b=0.
I have a load of questions, I'm only posting the ones I can't solve. Thanks!
Hi Bob
I uploaded a pdf file of the syllabus here:
http://www.filedropper.com/am27
Sorry, but it doesn't matter which to use. The title is misleading and your working is correct. Thanks again and I'm new to the forums, I will be posting frequent questions. This is because I am doing pure mathematics on my own and will sit for the exam.
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