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For example, (a+b)^n = sigma bla bla bla. so what is (a+b)! Expanded?
So is this as far as maths can possibly take us? What if (a+b)^(a+b)(-(1*2*3*4...a+b))
Ok but can you still expand (a+b)!
Surely (n-(n-1))! = (n-n-1)! = (0-1)! = (-1)! With bidmas
This is kind of basic compared to most of the stuff on the forum, but I was trying to find a definitive answer of n choose n-1. so n!/(n!(n-n-1)!) = n!/n!(-1)! and negatives don't have factorials. So I tried to expand (n-n-1)! To no avail. Does anyone have an answer? I tried (a+b)!(a+b-1)!(a+b-2)!.... (a+b-a+b)! But no idea how to do that.... Please help me!!
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