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#1 Re: Help Me ! » Help with box- and whiskers? » 2016-05-03 22:07:24
hi Melcalci
Welcome to the forum.
Had to look at the 'original' imgur image to clarify that scale.
The 'formulas' for determining the fixed points are lower quartile = (n+1)/4 median = (n+1)/2 and upper = (n+1)x3/4
For A the lower quartile is at 55 and n = 14. From above the LQ is at 15/4 =(we always ROUND DOWN??) 3 and 3/4 so the scores above this are 4th,5th,6th,7th,8th...14th = 11 scores in total.
For B the median is at 55 and n = 13. median is at (13+1)/2 = 7th score. So there are 6 scores above this.
4
So the total number of scores above or equal to 55 is 11 + 6 + 1 (the median for B) = 18.Bob
Can you explain why (x+1)/4 and not x/4?
#2 Re: Help Me ! » Help with box- and whiskers? » 2016-05-03 13:43:50
When blown up, it is not clear enough to read
http://www150.lunapic.com/editor/working/146232414950819?6889138799
I get 3/4(14) because the first line represents 1/4, this is 10.5. Bc 1/2 is where Team B is, they get 6 games, so 16.5.
I don't know how you could get 16, but that was the closest one so
#3 Help Me ! » Help with box- and whiskers? » 2016-05-03 12:57:25
- Mathegocart2
- Replies: 6
Help with 55?
I get 17, 3/4(Q1(Quartile 1))*14 + 1/2(median)*13 = 10
1/4 is bc. where I draw the line is 25%
#4 Re: Help Me ! » Statistics Prob? Don't know. » 2016-05-03 12:55:59
Nevermind I solved this.
#5 Re: Help Me ! » Statistics Prob? Don't know. » 2016-05-03 12:17:06
Hi;
What are A and B? What page are you looking at?
a and b are undefined rational numbers
#6 Help Me ! » Statistics Prob? Don't know. » 2016-05-03 09:33:14
- Mathegocart2
- Replies: 7
Hello MathIsFun,
I am having trouble with 48) in my Stats review packet
The mean of a data set is 45, the z-score for a is 0. The z-score for b is 0.2. What are THE POSSIBLE VALUES FOR a AND b
F) a=0 b=45.8
G)a=0 b=44.2
H) a=45 b=45.8
J)a=45 b=44.2
I think it is either C or D because a must be 45(z-score is 0) but I cannot determine B as I think it could be any value.
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