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I don't understand how you got <D + x + y = 90, from those three equations and I believe that you described the points wrong. did you mean G was the point where the two bisectors intersected?
Wait but is that it? What do I do after it. I am confused. Is there anyway you could explain it more thoroughly?
Wait I am confused, what do I label P, and what do I label S
Let
A_1, A_2 \cdots A_{12} be twelve equally spaced points on a circle with radius 1.
Find
(A_1 A_2)^2 + (A_1 A_3)^2 + \cdots + (A_{11} A_{12})^2
(The sum includes the square of the distance between any pair of points, so the sum includes
\binom{12}{2} = 66 terms.)
I have tried this attempting this problem multiple times, however, I keep on getting the same answer. I keep on getting 24. Can you help me?
Let ABCD be a cyclic quadrilateral. Let P be the intersection of AD and BC, and let Q be the intersection of AB and CD. Prove that the angle bisectors of angle DPC and angle AQD are perpendicular.
Can you guys please help me with this and give me some pointers?
to see image: http://latex.artofproblemsolving.com/9/b/b/9bbc27fba790f37537655605929bafb899150e5d.png
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