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Let
A_1, A_2 \cdots A_{12} be twelve equally spaced points on a circle with radius 1.
Find
(A_1 A_2)^2 + (A_1 A_3)^2 + \cdots + (A_{11} A_{12})^2
(The sum includes the square of the distance between any pair of points, so the sum includes
\binom{12}{2} = 66 terms.)
I have tried this attempting this problem multiple times, however, I keep on getting the same answer. I keep on getting 24. Can you help me?
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Hi;
This problem has been posted a couple of times on this forum and some advice given:
For an answer I am getting
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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