Math Is Fun Forum
You are not logged in.
- Topics: Active | Unanswered
Pages: 1
#1 Re: Help Me ! » yet another complex number problem » 2016-08-11 22:08:24
Yes, thank you very much for that kickstart.
#2 Help Me ! » yet another complex number problem » 2016-08-11 20:43:27
- xiaozaiz
- Replies: 4
I have no idea how to approach this question at all. I tried to sub (z-4i)/2 as Y and solved for Y but i dont know what to do with the answer i got. Would appreciate if someone could guide me along. You dont have to do the argand diagram part, i will settle that myself after i have understand how to solve this question. Thanks!
I placed the image for you - bobbym
#3 Re: Help Me ! » complex number problem » 2016-08-08 20:32:00
thank you guys for the help! I very much prefer completing the sq method suggested by thickhead as it is much easier for a student.
#4 Re: Help Me ! » complex number problem » 2016-08-08 04:46:26
Square both sides. Square root will go.
oh god how can i forget about that. Thanks
#5 Re: Help Me ! » complex number problem » 2016-08-08 04:44:59
Thanks for your fast reply. I am trying to show that x and y satisfy the second equation (given the first equation).
#6 Help Me ! » complex number problem » 2016-08-08 04:20:34
- xiaozaiz
- Replies: 7
Hi, i am having troubles solving the below problem
http://imgur.com/a/Jqf5c
I tried subbing in z=x+iy but i cant seem to remove the sqrt.
Can someone please guide me through solving this problem step-by-step. Thank you!
Pages: 1