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#1 Re: Help Me ! » 100% simple question! » 2025-07-13 19:02:17
The all solutions:
Only the last one is a real solution which approximates to 0.1966
#2 Re: Help Me ! » A simple question2 » 2025-07-12 23:52:07
Ok that's strange and I had never seen such thing before
#3 Re: Help Me ! » A simple question2 » 2025-07-12 23:29:46
Do you mean
Both are nearly 0This version used JavaScript for calculation. I was originally going to use Python and it's SymPy module to find exact answer but python denied the recursive loop as it reached it's recursion limit.
But how did you know this? Can you tell me your grade?
#4 Re: Help Me ! » A simple question2 » 2025-07-12 22:52:05
Hey dude, I calculated 100s of values and the final approximate answer was 0 as shown in the figure. You can see the complete execution at https://ktesla.infy.uk/math.html But only open if you are on a PC as this has various nested loops that might hang your computer a bit (3 GB RAM) 
#5 Re: Help Me ! » A simple question » 2025-07-12 03:36:47
Thanks!
We have two subjects Compulsary math and Optional maths.
#6 Re: Help Me ! » A simple question » 2025-07-12 02:28:23
Thanks Bob!
I'll definitely love that.
Tomorrow I have exam of Optional Mathematics and I'll ask my teacher about the question. Maybe he can help.
#7 Re: Help Me ! » A simple question » 2025-07-11 16:36:27
I tried 3 time with the Basel Problem:
I tried playing with it but still got nothing. I also tried learning Taylor, Fourier and Power series but all were complex.
This equation and our equation are related because they are terms of same pattern but you CANNOT find another using the first one. I only have a hope if Bob or any of us solves it.
#8 Re: Help Me ! » A simple question » 2025-07-11 14:51:39
Ok now I don't seek any way to prove the equation. I tried dozens of methods and the only thing I can say is -- This cant be proved using pure algebra. I may be wrong but I'll be still good if we get any solution.
#9 Re: Help Me ! » A simple question » 2025-07-10 20:41:28
After searching some pages of my copy, the question was:
which became :
Maybe I had some mistakes.... but the result was non elementary function.
#10 Re: Help Me ! » A simple question » 2025-07-10 20:24:53
I am in class 10 and I've started learning calculus (class 11) and after some time, when I'll find myself ready, I'll try learning Taylor Series and the Reimann zeta function. once I had a question something like
. I couldn't solve this and when I asked someone about it, they replied that this was a non elementary function an is written as Ei(x). That time I first saw Gamma and Zeta function.#11 Re: Help Me ! » LaTeX - A Crash Course » 2025-07-10 20:14:31
Hi Bob,
Ok last try. You just have to use this syntax (only change is that keep everything lowercased):
[MATH] your math codes... like \frac{1}{2} [/MATH] Examples:
[MATH] \sum_1^\infty x^2 [/MATH] produces (after changing MATH to math):
[MATH] \int sin(x)dx = - cos(x) + C [/MATH] produces:
[MATH] {\frac{\pi}{2}}^2 = \frac{\pi^2}{2^2} [/MATH] produces: Just keep in mind: use math instead of MATH. You can also see other's LATEX by typing on them. Try clicking:
Is this helpful?
#12 Re: Help Me ! » A simple question » 2025-07-10 19:58:19
Not actually because I'm just few years ahead of you and still I don't know much about Calculus. The only thing I know is that this can be proved using Taylor Series which is really complex. ?
#13 Re: Help Me ! » LaTeX - A Crash Course » 2025-07-10 19:52:37
Hello,
hypsin_0,Ok I know the reason you are getting confused. The main way is to use {math} tag at the starting and {/math} at the ending ( NOTE: keep in mind that there should be '[' and ']' instead of { and }).
To type a fraction:
{math} \frac{1}{2} {/math} (NOTE: The [] for {} only applies to the {math} and {/math}. Rest are same.) If you are still confused, visit this: https://ktesla.infy.uk/tex
#14 Re: Help Me ! » A simple question » 2025-07-10 17:53:39
This can be solved using calculus but to keep things easier, I just have a way: calculate everything from both LHS and RHS.
LHS = 1 + 1/16 + 1/81 + 1/256...... (notice that's decreasing rapidly when we increase n. So few numbers might give correct result. I'll use only 8 terms:)
= 1 + 0.0625 + 0.0123 + 0.00390625 + 0.0016 + 0.0007716049 + 0.000416493 + 0.0002441406
= 1.0815
RHS = 1.082
They are found to be equal up to 3 decimals and if you want more accuracy use more digits.
Was this helpful?
#15 Re: Help Me ! » Factorising harder quadratics » 2025-06-20 23:50:22
B^2 - 4AC = 121 + 240 = 361. This has root 19 so if I used the quadratic formula a simple 'solution' is available. That check saves wasting time looking for a factorisation if there isn't one.
Bob
True to Bob. The quadratic formula is better than any other methods as it works for all.
#16 Re: Help Me ! » Factorising harder quadratics » 2025-06-20 23:48:02
Hi guys!
In Nepal, we are mainly taught 3 ways of solving quadratic equations: product sum method, completing square method and the formula method. You can read the whole chapter here: https://lms.neemaacademy.com/course/2095/School-Mathematics-Grade-10/component/ynPP0L
In the product sum method, which only works for integers, we do the steps:
For any equation like:
, we do:- Multiply a with c to make ac
- Check whether it's sum or difference, if c > 0, it's sum else it's difference
- Find two numbers whose sum or difference is b and product is ac
- Once you have the numbers, keep them instead of b in the equation.
For example:
Here, ac = 6*(-10) = -60; use difference
The numbers whose product is 60 and difference is 11 are: 15 and 4.
Hence (2x+5) and (3x-2) are the solutions.
#17 Re: Exercises » Compute the solution: » 2025-06-04 02:18:42
#18 Re: Exercises » Compute the solution: » 2025-06-03 00:49:53
#19 Re: Help Me ! » cube root of x^6 » 2025-05-27 03:08:02
Hi,
In (xi), a = b because the powers are same and when you remove the powers; example by rooting both sides, you'll get the equation a=b. a^2 and b^2 are only equal if a and b are positive integers. Eg: 2^2 = x^2; then x = 2 or -2. 3^2 = y^2; y = 3 or -3............ You can check this yourselves.
#20 Re: Help Me ! » cube root of x^6 » 2025-05-25 11:11:41
Yes. Here's more from my Math's Book: 
#21 Re: Help Me ! » cube root of x^6 » 2025-05-23 15:26:45
Hi,
This might help:
#22 Jokes » Mars Jokes » 2025-05-22 11:29:08
- ktesla39
- Replies: 0
1. Why don’t Martians throw big parties?
Because they planet too far in advance!
2. What did Mars say to Saturn?
“Give me a ring sometime!”
3. Why did the rover break up with Mars?
Because it needed space.
4. What do Martians use to keep their pants up?
Asteroid belts.
5. Why did Mars get a job at the bakery?
It was great at making craters!
6. What’s a Martian’s favorite type of music?
Heavy meteor!
7. How do Martians throw a great party?
They make sure it’s out of this world!
8. Why don’t Martians use social media?
Because they’re afraid of Earth-ing their secrets!