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awesome!!! thank you!
i've converted it to .jpg
thank you Au..
I need it at home.. can you give me the code?
hey.. how do i put .gif in latex?
yes, site is wonderful..thank you very much for sharing
your site helped me..i just drew
no..i don't how to get it here..
great.. thank you bobbym and anonimnystefy
it's
\usepackage{ bbold }
\mathbb{1}
hi there.. does anybody know how do i get characterictic function (not \chi , i need symbol with 1 ) in latex? i can't find it..
i need help, i don't have much materials where i could read this..so, if there is anyone willing to help... i'd be thankful
find minimal polynomial over Q from (1+ i)/ (sqrt2)
determine all generators of Galois group 13th cyclotomic field Q_w13
you too!
both of you
i know.. it's because i didn't see that it's y>=1
i'm thankful to both of you Bobies
thank you!
i'm getting pi*176/3 in both cases
http://en.wikipedia.org/wiki/Solid_of_revolution Cylinder method
i got
thanks .. i missed 1<=y part .. i drew y<=1
I'd like to check if i got correct answer
Find the volume of the solid generated by rotating the region trapped between
around the y-axis.i get
i was using formula
then
tnx R
let r be a commutative ring, I ideal in R and P r-module.
how should i prove that P/IP is module over R/I for multiplying (r+I,p+IP)-->rp+IP
and if P projective R-module, i have to prove P/IP is projective R/I-module
thanks
woow!!
thanks Ricky!
i thank him for sharing his knowledge..sth little to cheer u up
tnx Ricky
(2) = (6)?
(1),(2),(3),(5),(7),(8),(9) ?
don't know how check with 2 elements, sorry
i'm afraid i have to quit, i don't have much time left and have much things to learn
but thanks anyway...i really appreciate ur effort
i'm ashamed of my ignorance..
would it be a problem if u put a solution on these exerices and i tell what i don't understand..i'm sorry, i'm just stupid for this things and don't know the basic
tnx once again...i'm really thankful for everything what u've written
Ricky..thanks alot!!! i really appreciate ur help
so, 1 is out cause p=7 prime, |G|>1
can i say that A_8 has (8*7*6*5*4*3*2)/7 cycles of length 7, which means 5760 cycles 7-cycle
i get 960 subgroups of order 7 from this cycles..960=1(mod7) and 960| |A_6| ..??
#3 ..dont know
tnx Ricky
i only know Z/10Z={10Z, 1+10Z,2+10Z,....9+10Z}
2 is prime, but not irreducible
a) (0)^(-1)=0 , (1)^(-1)=1, (2)^(-1)=8, (3)^(-1)=7, (4)^(-1)=4,(5)^(-1)=5,(6)^(-1)=6,(7)^(-1)=3,(8)^(-1)=2,(9)^(-1)=9 ?
i'm desperate
could u pls help me to figure this out?