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Oh oops. Shouldn't do math late at night haha
For dL/dt I got (23+t)(0.5504+.0046t+0.0001t²) and for part c I got 14 ppm/yr.
I did it again and got the exact same answer.
Did I do the derivative right or was it in the simplifying? Thanks.
Ecologists estimate that when the population of a certain city is p thousand persons, the average level L of carbon monoxide in the air above the city will be L ppm (parts per million), where L=10+0.4p+0.0001p². The population of the city is estimated to be p=752+23t+0.5t² thousand persons t years from the present.
a)Find the rate of change of carbon monoxide with respect to time.
I got: L=10+4(752+23t+0.5t²)+0.0001(752+23t+0.5t²)²
dL/dt = 4(23+t)+0.0002((752+23t+0.5t²)(23+t)
=(23+t)(4.1504+0.0046t+0.0001t²)
b)Find the time rate of change of the population (the rate of change of the population with respect to time)
I got: dp/dt = 23+t
c)How fast (with respect to time) is the carbon monoxide level changing at time t=2?
You would use the dL/dt right and substitute 2 in for t? I got the answer of 104 ppm/yr but I think that sounds high so I'm not sure.
Any help is appreciated!
The volume V of a spherical cancer tumor is given by V = [pi]x³/6, where x is the diameter of the tumor. A physician estimates that the diameter is growing at a rate of .4 millimeters per day, at a time when the diameter is already 10 millimeters. How fast is the volume of the tumor changing at that time?
I'm not sure how to solve this. I know that .4 is dx/dt but I don't know how to find dV/dt because only one equation is given.
Find the equation of the tangent line to the graph x³y^9 = 1 at the point (64, .25) and (64, -.25).
I found the correct equation for the first point, but I can't figure out the second point (64,-.25).
I got y= (1/768)x-(1/3) but mymathlab says that it is wrong.
I also can't figure out this problem.
Suppose that x and y are both differential functions of t and are related by the given equation. Use implicit differentiation with respect to t to determine dy/dt in terms of x, y and dx/dt
I got dy/dt = (-3x² dx/dt - 3y dx/dt) / (3x-7y^6) but I am not sure if that is right.
Suppose that x and y are related by the given equation and use implicit differentiation to determine dy/dx
4x^5 + y = 4y^5 + x
I got the answer (-20x^4 - 1)/(20y^4 - 1). Is that right?
Find the x-coordinates of all points on the curve y=(-x²+10x-21)³ with a horizontal tangent line.
I got y'=3(-x²+10x-21)²(-2x+10) for the derivative but I am not sure if that is right. Once I have the right derivative I just set the derivative equal to 0 and solve for x right? When I solved I got x=3,7 but MyMathLab told me I was wrong.
Find the equation of the line tangent to the graph of y=5x(x²-4x+5)^4 at the point (2,10).
I got that y'=5(x²-4x+5)³(8x²-16x). I don't know if that is right. Once I get the derivative figured out do I just put 2 in for x and solve?
Ecologists estimate that, when the population of a certain city is x thousand persons, the average level L of carbon monoxide in the air above the city will be L ppm (parts per million), where L=50+0.4x+0.0006x². The population of the city is estimated to be x=752+23t+0.5t² thousand persons t years from the present. Find the rate of change of carbon monoxide with respect to the population of the city, and the time rate of change of the population when t=2. How fast (with respect to time) is the carbon monoxide level changing at time t=2.
I don't even know where to begin. Can you explain what I need to do and how to set up the equation please?
y= (13x)/(1+.25x)² for x≥0
Find the coordinates of the maximum point.
I got y'=[13+6.5x-12.9x²]/(1+.25)² but when I set that equal to 0 and then used the quadratic equation to solve, I got a negative number under the radical, so I know that I did something wrong. I can't figure this one out.
The get the max min of f'(t) you would set f"(t) equal to 0.
I got f'(t)=15 and f"t=-60.
Would f"(t) be (-30)/(t+15)³ + 1350/(t+15)^4?
You would set f'(t) equal to 0 and determine whats a maximum to get the answer right? I'm not sure how to solve f'(t).
Yeah I need help. I've done the problem like 5 times and I keep getting that as an answer.
Is f'(t) 15/(t+15)² - (510)/(t+15)³?
[(3x+5)²-6(x+7)(3x+5)]/(3x+5)^4
I got that f'(t)= -(15)/(t+15)² - (510)/(t+15)³
I got f"t = (30)/(t+15)³ + (1530)/(t+15)^4
I don't know if those are right and I don't know how to solve them for 0.
Let f(t) be the amount of oxygen (in suitable units) in a lake t days after sewage is dumped into the lake, and suppose that f(t) is given approximately by the following. At what time is the oxygen content increasing the fastest?
f(t) = 1 - [(15)/(t+15)] + [(225)/(t+15)²]
Find the dimensions of a closed rectangular box with a square base and volume 125 in³ that can be constructed from the least amount of material.
What are the dimensions of the box?
The length of one side of the base is _____ in.
The height of the box is _____ in.
Thanks! I was just missing that extra zero. I was working on it late after studying for a calc test all day.
Let f(x) be the number (in thousands) of computers sold when the price is x hundred dollars per computer. Interpret the statements f(23)=30 and f'(23)=-6. Then estimate the number of computers sold if the price is set at $2325 per computer.
f(23)=30 implies that 30,000 computers are sold when the price is set at $2300.
f'(23)=-6 implies that when the price is $2300, for every $100 price increase, the sales decrease by 6,000 computers.
If computers are sold for $2325 per computer, how many computers will be sold?
I got 2850 computers, but MyMathLab says that isn't right.
An object moving in a straight line travels s(t) kilometers in t hours, where s(t)=7t²+t.
(a) What is the object's velocity when t=6?
(b) How far has the object traveled in 6 hours?
(c) When is the object traveling at a rate of 6 km/h?
For (a) I got: 85 km/h
For (b) I got: 258 km.
I can't figure out (c). Please help.
Thank you! That was right.
(a)Let A(x) denote the number (in hundreds) of computers sold when x thousand dollars is spent on advertising. Represent the following statement by equations involving A or A': When four thousand dollars were spent on advertising the number of computers sold was 1100 and it was rising at the rate of 80 computers for each 1000 dollars spent on advertising.
(b)Estimate the number of computers that will be sold if $6000 is spent on advertising.
For part a I got: A(4)=11 and A'(4)=0.8
I don't know how to do part b. Any help would be appreciated.