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y= (13x)/(1+.25x)² for x≥0
Find the coordinates of the maximum point.
I got y'=[13+6.5x-12.9x²]/(1+.25)² but when I set that equal to 0 and then used the quadratic equation to solve, I got a negative number under the radical, so I know that I did something wrong. I can't figure this one out.
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Hi taylor_2009;
x = 4
Maximum occurs at (4,13)
Graph f(x) to check:
http://www.mathsisfun.com/graph/functio … 4.12591175
Indeed their is a maximum at x = 4.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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