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T is a statistic test that is a normal null distribution. So, if the test rejects for large values of T, what is the p-value corresponding to T= 1.50. So, would i use the P(Z >= ) = 1.5 And then use the table to find the value?
And, I need to find if the test rejects for large T, would I do this: 1- the value I found?
Thanks for your help.
Hi, so I am trying to understand this statement. There is a discrete random variable X that takes positive integers where E(X) = k = 1 to infinity P(X>= k). So, how would I add this to find the expected value of a geometric random variable?
For a geometric random variable the equation is P(X = k) = (1-p)^(k-1) * p. And, the expected equation is E(X) So, how would I make it go to infinity? Would I find the X<= k, and then 1 - of the answer? Thanks for you help.
Thank you so much for trying to help! :]
a) is referring to: What is the probability that it passes through? Sorry, I should've spaced out the question. Is using the distribution equation (density equation) that I used in my question right? Or do I find the marginal density?
A square mesh of wires has a diameter d, and the holes in the mesh are squares whose side length is w. A spherical particle of radius r is dropped on the mesh. What is the probability that it passes through? What is the probability that it fails to pass through if it is dropped n times?
a)
f(x,y) + {1/r, if x^2 + y^2 <= 1 and 0 otherwise.
It would be r^2
How would I solve this? would I find the marginal density?
b)
I was thinking of using binomial distribution to find the probability, since its talking about failure. So, would it be like this?
P(N, n) = (n C N ) * p ^ k * (1-p)^(N-n) would I just show this?
Thanks for your time.
Thanks so much! I got it!!!
Catherine would like to invite at least 5 of her friends to a party. Suppose each of her friends, if invited, independently agrees to come with probability 3/4. What is the probability that she will get 5 to agree to come if she invites 5 people?
The answer is (5 C 5) (0.75) ^5(0.25) ^0. So, where did the solution get 0.25???? Is there a formula for this?? Thanks
Why do you have to get the average? Is it because of the different shifts?? Thanks for replying.
A system runs three shifts. In a day, 1% of the items produced by the first shift are defective, 2% of the second shift's items are defective, and 5% of the third shift's items are defective. If the shifts all have the same productivity, what percentage of the items produced in a day are defective?
1/100 * 2/100 * 5/100 = 10/100 = 1/10, so 10% percent defective right?
If an item is defective, what is the probability that it was produced by the 3rd shift?
2% + 1% + 5% = 8% total, 5% / 8% = 0.625
Are these answers correct? Thank you for your time
Hi, I am struggling with this problem, so if anyone can tell me how to get the correct answer, I would really appreciate it
P(A) = 0.15, P(B) = 0.05, P(A or B) = 0.17
Find the probability that contains the event A but not event B.
I thought I could use P(A or B) - P(B) = 0.17-0.05= 0.12.
Is that right???
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