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T is a statistic test that is a normal null distribution. So, if the test rejects for large values of T, what is the p-value corresponding to T= 1.50. So, would i use the P(Z >= ) = 1.5 And then use the table to find the value?
And, I need to find if the test rejects for large T, would I do this: 1- the value I found?
Thanks for your help.
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Well you need to double the probability since it is a two-tail test
X'(y-Xβ)=0
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