Math Is Fun Forum

Hi John,

thanks for your info. Did you get 29% from a calculation ? I have a video about but I can't up load it, maybe it's seeable at : https://docs.google.com/leaf?id=0B9pGxyM9yy2fNDMxMjgyYWQtNjQ0Ny00NGYzLTllOTUtMzFkNmIwNGY1MTky&hl=en

Hi Bob,

yeah it's dumb, it's a link to google docs I have, but only me can see them.

Does there exists a 4-point eccentric case ? I cannot figure it out.

bye.

Hi, bob,

i thought there was a domain, but couldn't figure it out with geometry. Maybe it's the first case i fell upon, I used the sine theorem.
d/sin(60)=b/sin(180-60-45) [hope you can see the pics]

Do you think other possibilities with 3 touching spots are not possible ? I mean this would imply non concentric centers, and I don't know if it's possible to (un)screw in this eccentric case ? ( I could manage to upload pictures) :

I'll look at the equation and tell you if i manage to understand these.

cya.

Hi, nice to meet you,

we could start like : d/dx=d/dz*dz/dx+d/dzbar*dzbar/dx=d/dz+d/dzbar

Hi bob,

I finally got the 24, but with a computer program, after 100 multiplication, only 24 were different. Anyway, Thanks for your explanation of why it was not 48.

I haven't found yet the dimension, taken this 9 element function of 24 variable, how many are independent : it should be 4 or 8, but i need to write a code again (could it be that there were 9 linearly independent matrices in this set ?)

almost, I read we put complex numbers in the form of real matrices, but this "isomorphism" is maybe already too descriptive of the symbol i ?

Hi, ok.

By dimension I meant : the minimal number D of elements, so that a linear combination of these independent elements (now with a sum) give all the elements.

Anyhow in this case the field of coefficient cannot be continuous, but maybe

Hi, thx.

I had another question : Suppose we find 2 linearly independent i=sqrt(-1), with 2x2 matrices, let say I1, I2. I don't know If their product is spanneable by {1,I1,I2}, but if it were the case, were this a sufficient condition to build an algebra ?

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(there is more time than patience, but the world is imaginary small)

Hi, nice to meet you.

I looked at the Kronecker's method, but don't understand how it goes

for example : f(x)=x^8-x^7+x^5-x^4+x^3-x+1

I have f(0)=1, f(2)=151, f(-2)=331

if I look for a polynomial g(x)=ax^2+bx+c, fitted with the values above, got :
g(0)=1=>c=1
and a=60, b=-45.

and the following of it would be : if the coefficient are integer, and the discriminant <0 it should be dividable ?? (which here is not the case, since delta>0)

Hi, nice to meet you.

can we say : to be sold 60 apples at 25$,

6 apples at 2.50$ (or 5 at 2.083$, since 25$/12 non equals 2)

3 at 1.25$ but then w/o caring about the sort of apples.

programmers have noticed it's much easier to program an automatic insult generator than a worship generator.

and that death of people was always the same : enough money was put in the bet, that it was worth programming the death of with certainty : take bill with the more money corresponding, say the cause.

Hi, nice to meet you.

i think it works as distributing r1 i1 on comp2 :

comp1*comp2=(r1+i*i1)*(r2+i*i2)=r1*(r2+i*i2)+i*i1*(r2+i*i2)
=r1*r2+i*r1*i2+i*i1*r2+i*i1*i*i2=
=(r1*r2-i1*i2)+i(r1*i2+i1*r2)., since i*i=-1

or

realpart(comp1*comp2)=real1*real2-imag1*imag2
imagpart(comp1*comp2)=real1*imag2+imag2*real2

cya.