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#226 Re: Help Me ! » How to find the limit of a sum of a series? » 2008-03-24 05:25:31

How do I use this?

Can you give me an example of how to apply this?

#227 Re: Help Me ! » Another Logarithmic Equation problem » 2008-03-24 05:16:09

1.9393 and -1.9393

I solved this using TI-89 and gave me this same answers. The book must be wrong.

#229 Re: Help Me ! » How to work this out not sure? » 2008-03-24 04:06:59

hmm this is just basic arithmetic. Im not sure the explanation im going to give you is the best out there but lets say you want to take away 3.6 from 30. Maybe it would be easier for you to take away the whole number and then the decimal. For example, first you do 30 - 3 which you know = 27. And now you take away the decimal so 27 - 0.60 = 26.4

Another method if you dont want to deal with the decimals is to multiply both numbers by 10 (depends on how many decimals) and then divide the answer by 10.

For example, 30 - 3.6 so you multiply both numbers by 10 so you have 300 - 36 = 264 so now you divide 264 by 10 which is 26.4 but this is MUCH troublesome than just doing a regular subtraction with decimals...

#230 Re: Help Me ! » How to work this out not sure? » 2008-03-24 03:41:30

No. You need to take 12% of 30 and subtract that from 30.

12% of 30 = 30 x 0.12 = 3.6

30 - 3.6 = 26.4

£26.40 is your new price.

#231 Re: Help Me ! » Integral problem » 2008-03-24 03:11:21

Most substitutions are not necessary if you can do it in your head. With that said, it isnt necessary as you said but it simplifies the integral so its less troublesome for the people that are still learning.

Xingz, the integral you asked about is called an "improper integral" because your taking the integral over an infinite interval. As Identity mentioned, the way to handle such integral is to change the intervals such that:

In this case you have replaced infinity with k but since your taking the limit as k goes to infinity, its the same but it makes it possible for you to solve an otherwise unsolvable integral.

#232 Re: Help Me ! » How to find the limit of a sum of a series? » 2008-03-23 03:17:22

I was able to follow you but I feel that if I try to do it for any other that I wouldnt know how to continue. Could you please explain where did you get the idea of doing all those steps? Like I said, I understand them but I wouldnt know how to develop this steps for another problem.

I just decided to use the formula to solve them but I ran into some which I couldnt find a ratio....So I guess the series is not geometric?

For example:

and also this one:

#233 Re: Maths Is Fun - Suggestions and Comments » Chess » 2008-03-21 12:40:02

Last game I just murdered the computer.

1: e4  Nc6
2: f4  Nf6
3: Nc3  d6
4: Nf3  Be6
5: Be2  h5
6: Bb5  Qd7
7: Kg1  Kc8
8: f5  Bxf5
9: exf5  Qf5
10: Bxc6  bxc6
11: Nd4  Qd7
12: Qf3  Nh7
13: Nxc6  Re8
14: Nxa7  Kd8
15: Qa8  Qc8
16: Qxc8

Maybe you should allow for different levels of play? Its too easy to beat.

#234 Re: Maths Is Fun - Suggestions and Comments » Chess » 2008-03-21 12:36:54

The computer played a solid game and then had a few brainfarts even allowing me to do a very simple checkmate?

#235 Re: Help Me ! » How to find the limit of a sum of a series? » 2008-03-21 11:00:50

Thanks a lot Daniel123.

The thing is that we havent got to those formulas in the book. They want us to find its limit by actually taking the limit of the series.

This how they do it in the solutions manual:

85084328kf9.jpg

which gives the same answer as you specified but I'd like to do it this way but to be honest, I have no idea.

#236 Help Me ! » How to find the limit of a sum of a series? » 2008-03-21 10:37:43

LuisRodg
Replies: 11

Im doing my homework on Infinite Series and I need help how to find the limits of the sums of the series.

For example:

So I know that a = 1/4 and r = 1/4 and since:

The series converges.

This was just an example. How do I find the limits of such series?

#237 Re: Help Me ! » Reply me wit correct Answer plz » 2008-03-21 05:49:19

i dnt rlly undrstan wat ur tryin' to ask since u didn post a specific question.

#238 Re: Help Me ! » Help Solving Logarithmic Equations » 2008-03-20 11:08:13

Or you can just plug it in the TI-89 and be done with it.... which is what I did lol.

But yes, I'd someday like to find the time to teach myself how to factor all this kinds of equations. Im bad at factoring too.

#239 Re: Help Me ! » Help Solving Logarithmic Equations » 2008-03-20 03:47:32

logbase7(1-x) - logbase7(x+2) = logbase7(x^2)

logbase7((1-x)/(x+2)) = logbase7(x^2)
(1-x)/(x+2) = x^2
x^3 + 2x^2 + x - 1 = 0
x = 0.465571231877

#240 Re: Help Me ! » Discrete math » 2008-03-20 01:54:07

1) If there are no restrictions then you need to choose 12 out of 20. --- 20C12

2) 6 men and 6 women. 12C6 + 12C6

and I dont know how to do to 3 and 4.

Im a Discrete math student myself and we just started to do combinatorics and permutations so maybe my 2 answers are wrong and I'd like to know the answer to the last parts.

#242 Re: Puzzles and Games » Stupidly hard quiz » 2008-03-16 05:19:55

I was able to find 2 questions logically. (#10 and #16).

However, I think this quiz is impossible because of questions like this:

19. The answer to this question is:
AA
BB
CC
DD
EE

WTF?

#243 Re: Help Me ! » trigo (a-level) » 2008-03-16 04:50:24

Does this constitute an "Advanced" program or is this the general educational setup for everyone?

I live in the US, and back when I was in High School I was part of the IB program (International Baccalaureate) which in fact is an European program and it had a similar setup in the sense that you chose 3 HL (Higher Level) and 3 SL (Standard Level) classes. But this was in the same year.

#244 Re: Coder's Corner » help me with this log code » 2008-03-16 04:38:31

The function takes in the number in double and the base in integer such that when the function is called:

When we are trying to find the log of x to the base of b equals "I" then this is the same as:

and this is the same that this code is using.

First of all if the log number is negative, this code gives an error because logs are only defined for Number > 0.

If our number is nonnegative then the code proceeds and we enter a For loop from I = 0 to Number. The first check this For loop does is to see if Base ^ I = Number because if thats the case, it means that "I" is our answer to the log, therefore if thats the case then we just say that LogB=I and exit the function because we just found it.

If this is not the case then the For loop does another check and this check is to see if Base^I is less than the Number and Base^(I+1) is greater than the Number. The loop will continue looping until we find that I that makes Base^I less than Number and Base^(I+1) greater than Number. When we find this I value, this means that the answer to the log is between I and (I+1) and this is because of what we said before.

Remember that when we had a log, it was the same as this:

Base^I = Number

So in the code, if we have:

Base^I < Number
Base^(I+1) > Number

that tells us that the log is greater than I and less (I+1) so our answer is in the interval (I,I+1).

Ok, so now that we know our answer must be between I and (I+1) then the code creates another For loop which runs from 0 to 99999 and what this does is that it keeps adding 0.00001 to Lg (Lg = I) and keeps checking if Lg is our answer. We are bound to find it because we knew that our answer was between I and I+1 so if kept adding 0.00001 to I and checking, add another 0.00001 and check again, ..... , eventually we will find our answer to the log.

#245 Re: Help Me ! » trigo (a-level) » 2008-03-16 04:28:06

No problem.

What is this "a-level" you put in the topic?

#246 Re: Help Me ! » trigo (a-level) » 2008-03-16 04:02:55

Thanks Daniel. I *always* have problems with this latex lol!

#247 Re: Help Me ! » trigo (a-level) » 2008-03-16 03:51:35

Finding the gradient just means finding the slope or the value of the derivative (dy/dx) at the specified x value.

So if you have:

This is the same as just plugging in the x:

#248 Re: Maths Is Fun - Suggestions and Comments » Parking Lot Game » 2008-03-15 13:56:02

Hah I beat the game! I won level 14 how you said and then beat the last level!

Nice game.

#250 Re: Help Me ! » Pascals triangle » 2008-03-14 00:10:00

By inspection I found that there are 10 routes if you can only move south and east. However, I wouldnt know how to help you with the use of Pascal's triangle.

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