You are not logged in.
How do I use this?
Can you give me an example of how to apply this?
1.9393 and -1.9393
I solved this using TI-89 and gave me this same answers. The book must be wrong.
hmm this is just basic arithmetic. Im not sure the explanation im going to give you is the best out there but lets say you want to take away 3.6 from 30. Maybe it would be easier for you to take away the whole number and then the decimal. For example, first you do 30 - 3 which you know = 27. And now you take away the decimal so 27 - 0.60 = 26.4
Another method if you dont want to deal with the decimals is to multiply both numbers by 10 (depends on how many decimals) and then divide the answer by 10.
For example, 30 - 3.6 so you multiply both numbers by 10 so you have 300 - 36 = 264 so now you divide 264 by 10 which is 26.4 but this is MUCH troublesome than just doing a regular subtraction with decimals...
No. You need to take 12% of 30 and subtract that from 30.
12% of 30 = 30 x 0.12 = 3.6
30 - 3.6 = 26.4
£26.40 is your new price.
Most substitutions are not necessary if you can do it in your head. With that said, it isnt necessary as you said but it simplifies the integral so its less troublesome for the people that are still learning.
Xingz, the integral you asked about is called an "improper integral" because your taking the integral over an infinite interval. As Identity mentioned, the way to handle such integral is to change the intervals such that:
In this case you have replaced infinity with k but since your taking the limit as k goes to infinity, its the same but it makes it possible for you to solve an otherwise unsolvable integral.
I was able to follow you but I feel that if I try to do it for any other that I wouldnt know how to continue. Could you please explain where did you get the idea of doing all those steps? Like I said, I understand them but I wouldnt know how to develop this steps for another problem.
I just decided to use the formula to solve them but I ran into some which I couldnt find a ratio....So I guess the series is not geometric?
For example:
and also this one:
Last game I just murdered the computer.
1: e4 Nc6
2: f4 Nf6
3: Nc3 d6
4: Nf3 Be6
5: Be2 h5
6: Bb5 Qd7
7: Kg1 Kc8
8: f5 Bxf5
9: exf5 Qf5
10: Bxc6 bxc6
11: Nd4 Qd7
12: Qf3 Nh7
13: Nxc6 Re8
14: Nxa7 Kd8
15: Qa8 Qc8
16: Qxc8
Maybe you should allow for different levels of play? Its too easy to beat.
The computer played a solid game and then had a few brainfarts even allowing me to do a very simple checkmate?
Thanks a lot Daniel123.
The thing is that we havent got to those formulas in the book. They want us to find its limit by actually taking the limit of the series.
This how they do it in the solutions manual:

which gives the same answer as you specified but I'd like to do it this way but to be honest, I have no idea.
Im doing my homework on Infinite Series and I need help how to find the limits of the sums of the series.
For example:
So I know that a = 1/4 and r = 1/4 and since:
The series converges.
This was just an example. How do I find the limits of such series?
i dnt rlly undrstan wat ur tryin' to ask since u didn post a specific question.
Or you can just plug it in the TI-89 and be done with it.... which is what I did lol.
But yes, I'd someday like to find the time to teach myself how to factor all this kinds of equations. Im bad at factoring too.
logbase7(1-x) - logbase7(x+2) = logbase7(x^2)
logbase7((1-x)/(x+2)) = logbase7(x^2)
(1-x)/(x+2) = x^2
x^3 + 2x^2 + x - 1 = 0
x = 0.465571231877
1) If there are no restrictions then you need to choose 12 out of 20. --- 20C12
2) 6 men and 6 women. 12C6 + 12C6
and I dont know how to do to 3 and 4.
Im a Discrete math student myself and we just started to do combinatorics and permutations so maybe my 2 answers are wrong and I'd like to know the answer to the last parts.
"loois"
I was able to find 2 questions logically. (#10 and #16).
However, I think this quiz is impossible because of questions like this:
19. The answer to this question is:
AA
BB
CC
DD
EE
WTF?
Does this constitute an "Advanced" program or is this the general educational setup for everyone?
I live in the US, and back when I was in High School I was part of the IB program (International Baccalaureate) which in fact is an European program and it had a similar setup in the sense that you chose 3 HL (Higher Level) and 3 SL (Standard Level) classes. But this was in the same year.
The function takes in the number in double and the base in integer such that when the function is called:
When we are trying to find the log of x to the base of b equals "I" then this is the same as:
and this is the same that this code is using.
First of all if the log number is negative, this code gives an error because logs are only defined for Number > 0.
If our number is nonnegative then the code proceeds and we enter a For loop from I = 0 to Number. The first check this For loop does is to see if Base ^ I = Number because if thats the case, it means that "I" is our answer to the log, therefore if thats the case then we just say that LogB=I and exit the function because we just found it.
If this is not the case then the For loop does another check and this check is to see if Base^I is less than the Number and Base^(I+1) is greater than the Number. The loop will continue looping until we find that I that makes Base^I less than Number and Base^(I+1) greater than Number. When we find this I value, this means that the answer to the log is between I and (I+1) and this is because of what we said before.
Remember that when we had a log, it was the same as this:
Base^I = Number
So in the code, if we have:
Base^I < Number
Base^(I+1) > Number
that tells us that the log is greater than I and less (I+1) so our answer is in the interval (I,I+1).
Ok, so now that we know our answer must be between I and (I+1) then the code creates another For loop which runs from 0 to 99999 and what this does is that it keeps adding 0.00001 to Lg (Lg = I) and keeps checking if Lg is our answer. We are bound to find it because we knew that our answer was between I and I+1 so if kept adding 0.00001 to I and checking, add another 0.00001 and check again, ..... , eventually we will find our answer to the log.
No problem.
What is this "a-level" you put in the topic?
Thanks Daniel. I *always* have problems with this latex lol!
Finding the gradient just means finding the slope or the value of the derivative (dy/dx) at the specified x value.
So if you have:
This is the same as just plugging in the x:
Hah I beat the game! I won level 14 how you said and then beat the last level!
Nice game.
Interesting game.
Thanks for sharing.
By inspection I found that there are 10 routes if you can only move south and east. However, I wouldnt know how to help you with the use of Pascal's triangle.