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#226 Re: Help Me ! » Brilliant app - Does my courses done on premium stay after ending? » 2023-09-23 16:43:15

Aly wrote:

Hello, I've purchased Brilliant app, and I've been wondering if anyone could answer me if after the month that I've paid for Premium, if I cancel my subscription for the next month, does the progress I've done on some courses stay? Like are those courses I've done while I had the premium subscription stay available to redo after subscription if I want to?

dunno if ne1 else here has used the app
Google Play: https://play.google.com/store/apps/deta … n_US&gl=US
Apple App Store: https://apps.apple.com/us/app/brilliant … d913335252
maybe u can contact brilliant & ask?
https://help.brilliant.org/en/collectio … ct-support
gud luck!

#227 Re: Help Me ! » Sides of A Right Triangle » 2023-09-23 16:37:56

harpazo1965 wrote:

Suppose that m and n are positive integers with m > n.
If a = (m^2 - n^2), b = 2mn, and c = (m^2 + n^2), show that a, b, and c are the lengths of the sides of a right triangle. 

Note: This formula can be used to find the sides of a right triangle that are integers such as 3, 4, 5; 5, 12, 13; and so on. Such triplets of integers are called Pythagorean triplets.

NOTE: Looking for the set up only.

e_jane_aran wrote:

I suspect that they're expecting you to notice how the given side-length expressions hint of connections to perfect-square trinomiais.

If you add two of the above expressions, you get the third of the above expressions. Which pair works?

big_smile

harpazo1965 wrote:

If I add a^2 [and] c^2, the middle term cancels out. This does not leave me with much to play with.

If I do that, I am left with m^4 + n^4 twice. In other words, I get
2(m^4 + n^4) = 2m^4 + 2n^4, which does not represent b^2.

so maybe try a different pair of terms? (there r 2 other pairs; 1 of them works)

#231 Re: Exercises » Compute the solution: » 2023-09-22 04:27:22

Jai Ganesh wrote:

1906.

if the fenced-in area is to be a rectangle dont u have 2 use 78 m by 39 m?

#232 Re: Jai Ganesh's Puzzles » 10 second questions » 2023-09-22 04:22:58

Jai Ganesh wrote:

#8915.

multiplying to +24 (so factor have same sign)
adding to -11 (so factors are nbegative)

#233 Re: Jai Ganesh's Puzzles » Oral puzzles » 2023-09-22 04:19:47

Jai Ganesh wrote:

#5921.


it helps 2 factor 1st

#234 Re: Jai Ganesh's Puzzles » 10 second questions » 2023-09-21 04:55:57

Bob wrote:

Nearly; but you have a 3 too many.  In your box 3y times 3y doesn't make 3y^2.

Bob

lol

box:

       3y    -10
    +------+------+
  y | 3y^2 | -10y |
    +------+------+
 -3 |  -9y |  +30 |
    +------+------+

thx!

#235 Re: Jai Ganesh's Puzzles » 10 second questions » 2023-09-21 02:12:18

Jai Ganesh wrote:

#8914.

Takes way longer to type out than to solve.

#238 Re: Jai Ganesh's Puzzles » Doc, Doc! » 2023-09-19 18:50:02

Jai Ganesh wrote:

#2350. What does the medical term Fibromyalgia mean?

its a disease that makes everything rly hurt

#239 Re: Jai Ganesh's Puzzles » English language puzzles » 2023-09-19 18:47:09

Jai Ganesh wrote:

#5593. What does the noun presage mean?

isnt presage a verb meaning something like 'to warn or give notice of'?

Jai Ganesh wrote:

#5594. What does the adjective prescriptive mean?

making ppl follow a rule

#240 Re: Computer Math » Calculator » 2023-09-19 18:43:12

Rotbling wrote:

They have a calculator without Scientific Notation?!
Wow!

which calc u mean? maybe is mode selection?

#241 Re: Exercises » Compute the solution: » 2023-09-19 18:40:08

Jai Ganesh wrote:

1903.

square side length: x
lawn area: x^2
whole area: (x+8)^2
path area: 16x+64=196
x=8.25m

#242 Re: Exercises » Task Pack 1(equations and system of equations) » 2023-09-19 18:32:25

Shiver wrote:

1. Solve this equation: 3x-2+-6=4(x²+2x)2.

what is 2. at end? a square?

Shiver wrote:

2. Solve this equation: ln(4x)=(x-cos(x²))(3x-2)3.

what is 3. at end? (i dont think u can solve this w/ algebra; have to use numeric approx)

Shiver wrote:

3. create an linear system of equations where x=2,y=0 and z=2.5  4.

pick numbers for x,y,z. use what they gave you to get values.

e.g. 3x+2y+4z=3*2+2*0+4*2.5 = 6+0+10 = 16 so eqn is 3x+2y+4z=16

now do two more to get system

Shiver wrote:

Let a³x²+b²x+c=0. What values are a,b,c if a < b and c = 4a

put 4a in for c: a^3x^2+b^2x+4a=0

do quad fiormula for x in terms of a&b

do cases. e.g. if x=0 then what? (a=0 and b>0 so infinite sol'n set)

try other cases

(https://www.wolframalpha.com/input?i=a%5E3+x%5E2+%2B+b%5E2+x+%2B+4a+%3D+0%2C+a+%3C+b)

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