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I don't understand it well !!!!
Please explain this question
F(x)=sin(x) x belongs (-pi,pi)
Now we must differentiate the a^2. But 'a' is a constant. It's gradient function is zero whatever x is.
What is gradient function!!!!
Dy /dx is not equal to zero but da\dx is zro plz explain? ??
Why we differentate wrt x???
If you have not met this rule before, please ask about it.
Hehe I am well aware
Minus y divide by x is ans
When we take dy/dx it's not equal to zero when we take da/dx it's equal to zero how ????
It's second derivative
I solve dy by dx how further solve for y2
Help for this question
Find y2
X^2+y^2=a^2
The only roots are 0 and 0. So (0,1) is a possible local extreme.
Why you not wote (0,1)
How y axis is 1
Why
We set that to 0 and solve:
i perform all calculatiions in differntiation but this topic i dont understand
same /
yes its complete question its maxima and minima method
i calculate it but how squre root is sperate on.each value
How it leads to same result and show these lead to the same result.
Find the extreme values for the function defined as
f (x)=1-x^3
I need how to solve it
Plese show me method of differntiate
Yes bob
What is extreme values and question explain
Find the extreme values for the function defined as
f (x)=1-x^3
Please help me in this question
Question
Determine the interval in which f is increasing or decreasing for the domain mentioned
F(x)=sin(x) x belongs (-pi,pi)
2nd question
And f(x)=cos(x) x belongs to (-pi÷2,pi÷2)
Hi all;
I have simple problem of this concept that is
If there is sqrt 2 divided by sqrt 9
Then how we say (2÷9)whole sqrt
Hmm e^x at 1 is difficult to compute so which series used