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#1 2017-03-08 17:51:04
- Zeeshan 01
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- Registered: 2016-07-22
- Posts: 746
Extreme values
What is extreme values and question explain
Find the extreme values for the function defined as
f (x)=1-x^3
Malik
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#2 2017-03-08 20:25:57
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Extreme values
You are looking for the maxima and minima? You will need calculus for that. You could compute them easy enough. So, what type of answer are you looking for?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#3 2017-03-09 00:02:19
- Zeeshan 01
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- Registered: 2016-07-22
- Posts: 746
Re: Extreme values
Find the extreme values for the function defined as
f (x)=1-x^3
I need how to solve it
Malik
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#4 2017-03-09 01:17:52
- Bob
- Administrator
- Registered: 2010-06-20
- Posts: 10,621
Re: Extreme values
The extreme value theorem is here:
https://www.khanacademy.org/math/ap-cal … ue-theorem
If that function has no defined domain then the extremes are + and - infinity. But I would expect to have been given a range of values for x. Are you sure you are giving us the whole question?
Bob
Children are not defined by school ...........The Fonz
You cannot teach a man anything; you can only help him find it within himself..........Galileo Galilei
Sometimes I deliberately make mistakes, just to test you! …………….Bob 
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#5 2017-03-09 01:24:37
- Zeeshan 01
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- Registered: 2016-07-22
- Posts: 746
Re: Extreme values
yes its complete question its maxima and minima method
Malik
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#6 2017-03-09 01:52:05
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Extreme values
Hi;
To find candidates to be a local extreme we differentiate the function.
We set that to 0 and solve:
The only roots are 0 and 0. So (0,1) is a possible local extreme.
But using the second derivative test
we see that 1 - x^3 does not have a maxima or a minima at x = 0 so I would say that 1 - x^3 does not have any local extremes.
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#7 2017-03-10 15:01:24
- Zeeshan 01
- Member
- Registered: 2016-07-22
- Posts: 746
Re: Extreme values
Why
We set that to 0 and solve:
Malik
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#8 2017-03-10 15:03:27
- Zeeshan 01
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- Registered: 2016-07-22
- Posts: 746
Re: Extreme values
The only roots are 0 and 0. So (0,1) is a possible local extreme.
Why you not wote (0,1)
How y axis is 1
Malik
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#9 2017-03-10 16:10:20
- bobbym
- bumpkin
- From: Bumpkinland
- Registered: 2009-04-12
- Posts: 109,606
Re: Extreme values
When you put x = 0 into y = 1 -x^3 you get 1. Therefore the point is (0,1).
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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#10 2017-03-12 01:00:49
- CIV
- Member
- Registered: 2014-11-09
- Posts: 74
Re: Extreme values
The only roots are 0 and 0. So (0,1) is a possible local extreme.
Why you not wote (0,1)
How y axis is 1
The location of the extrema is x = 0. The location of the tangent line, when it's slope is zero, is (0,1)
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