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#26 Help Me ! » mixed algebra fractions » 2014-01-10 03:18:36
- bronxsystem
- Replies: 2
bah i tried not to make thread i can do most of the problem its just the last part i get stuck. i dont understand why the answer has +4 ><
change fraction into mixed expression
i can get the answer
the book says
but where do they get the +4 from ><
i divided
by a, then quotient 2athen i multiply the divisor which gives me i put this under the dividend and subtract
i get answer
i divide -a by a which is 1 and i put that in quotient.
this is where i get stuck i think
i multiply the divisor by -1 and get
bah i think i just got it
(-2) - (- 2) = +4
#27 Re: Help Me ! » Algebra Mixed Fractions » 2014-01-09 23:33:41
arghh i didnt just mess up the last part i messed up 2 terms
i got the answer
thank youu now i will redo chapter to make sure i dont forget it lol
#28 Re: Help Me ! » Algebra Mixed Fractions » 2014-01-09 23:26:52
i will try it again i think i can get it
#29 Re: Help Me ! » Algebra Mixed Fractions » 2014-01-09 23:19:11
ooooooooooooooooooooooooooooooooooooo
yeah i see what happened
thank you
icicicicic i understand now
#30 Re: Help Me ! » Algebra Mixed Fractions » 2014-01-09 23:12:12
any chance can aware me how to fix it S: i answered all the other exercises in the section and its just this one i keep getting wrong. my brain is blank ><
#31 Re: Help Me ! » Algebra Mixed Fractions » 2014-01-09 23:02:58
hrmm sorry >< i thought we dont need to touch last fraction because it already has the lowest common denominator (a- 2b)
if i mulitply the
with the negative i get>< not sure how to get the last part right
#32 Re: Help Me ! » Algebra Mixed Fractions » 2014-01-09 22:50:24
is the first step
is that right so far??
because i get confused with this
is it#33 Re: Help Me ! » Algebra Mixed Fractions » 2014-01-09 22:17:48
is my working correct S:
i got answer right but did i format it right
#34 Help Me ! » Algebra Mixed Fractions » 2014-01-09 22:13:10
- bronxsystem
- Replies: 15
really stuck. I have tried to do this several times and i cant get the right answer.
would appreciate any help
this step i get confused with the
did i correctly make it negative? because the product will be but i do this i get wrong answerthe product of the -b^2 is now seems weird did i do that right?
to get this answer i multiplied the numerator by -1 and added negative in front of the fraction to keep the value i understand that
is that right im bit confused ><
as i write this i think i realised what happened.
#35 Re: Help Me ! » Combine Algebra Fractions » 2014-01-09 05:51:44
YEEEEEEEEAH someone helped me out
problem was the x + 1 cancel out after i factor the numerator.
#36 Help Me ! » Combine Algebra Fractions » 2014-01-09 05:26:49
- bronxsystem
- Replies: 2
I have been going through these exercises and have been doing ok until i got to this question. What confuses me is the lowest common denominator and i get the answer wrong 
my answer is sooo far off the book ><
Is the LCD
maybe this step is what i messed up i changed the sign of the fraction because i reversed1-x to x-1
any advice much appreciated thank you
the books answer said the denominator will be x - 1 how is that possible when in the denominator of the 3rd fraction was
#37 Re: Help Me ! » basic factoring problem confused » 2014-01-06 06:32:03
awesome thanks
#38 Re: Help Me ! » basic factoring problem confused » 2014-01-06 06:00:03
oops its
3tp (4t + 1)(t - 1 )
i think S:
#39 Help Me ! » basic factoring problem confused » 2014-01-06 04:09:35
- bronxsystem
- Replies: 6
Hey all im confused with this problem i can get the answer, however i do something that seems wrong.
Factor
12t^3 p - 3tp - 9t^2 p
= 3tp (4t^2 - 1 - 3t)
= 3tp (4t^2 - 3t - 1) this step, sorry for sounding silly but am i allowed to just swap it around like this? is it allowed because im multiplying by 3tp?
= 3tp (4t - 1) (t + 1)
been up for while my brain fried but feels wrong switching it around 
#40 Re: Help Me ! » convert sum od exponents into product of exponents » 2013-07-16 09:34:37
Is there a way to go from having a^2+b^2=c^2 to a^2*b^2=c^2, in order for me to add the exponents if they have the same base?
Can someone please help me with this?
Thanks in advance!
maybe i shouldnt post since i might be wayy off and your talking about something else
but you add exponents when your multiplying like terms eg
when your just adding
you keep exponent
or are you talking about something else and now i look silly 
#41 Re: Help Me ! » combining algebra fractions » 2013-07-16 03:33:34
hey rete thanks for reply
i followed what you wrote makes sense
#42 Re: Help Me ! » combining algebra fractions » 2013-07-15 15:43:46
how would you write the final answer?
because if i just change the numbers its just 1/1 right S:
sorry i should stop posting after ive stayed up all night 
#43 Re: Help Me ! » combining algebra fractions » 2013-07-15 12:08:24
i mean to reduce the fraction
eg 50/50 would just be 1/1 what rule am i missing with the -d^2
prob very silly question but cant get it out of my head
or
this is already reduced right? derp derp (:#44 Help Me ! » combining algebra fractions » 2013-07-15 10:41:52
- bronxsystem
- Replies: 6
hey all i have very basic question but i dont understand why my answer is different
i get the answer
however the book says
why cant we remove the -d^2? is it because dividing both negative numbers makes a positive or something S:
#45 Re: Help Me ! » Multiplying fractions » 2013-07-14 04:22:53
roger thanks
#46 Re: Help Me ! » Multiplying fractions » 2013-07-14 00:30:38
sorry those other 2 post had to much fluff a better question maybe is do you think the steps i take are acceptable?
eg
(3ab^2 / 4) * ( 12/ 18a^2)
just simply multiply numerators then denominators and then simplify
(36ab^2) / (72a^2)
then divide by common factor 36a
= b^2 / 2a
thats all it is right?
not sure why this way works i thought your meant to divide both numerator and denominator by same number S:
(3ab^2 / 4) * (12 / 18a^2)
first divide numerators by common factor 3
4ab^2
then divide denominators by common factor 2
2 (8a^2)
then divide both numerators and denominators by 2
(2ab^2 / 4a^2)
then divide by 2a
( b^2 / 2a)
#47 Re: Help Me ! » Multiplying fractions » 2013-07-13 12:35:24
had another one that the method works but again not sure what im doing S:
( a + 3 / a - 5) * (2a - 10 / 3a + 9)
= (a + 3 / a - 5) * 2 ( a - 5) / 3 (a + 3)
then just divide numerator and denominators by common factors and i get 2/3
>< whats this called or what rule is it?
#48 Help Me ! » Multiplying fractions » 2013-07-13 12:23:51
- bronxsystem
- Replies: 6
Hey all i know this is really basic but i have hit a wall
(d / a+b) * (5a + 5b / 2d^2 + 2d)
i can get the answer but im not sure what im actually doing S:
i khow to multiply problem like (1/2) * (1/2) = 1/4 but what confuses me in this problem is the denominator a+b not sure how to multiply the other denominator with it.
My workings
(d / a+b) * (5a + 5b / 2d^2 + 2d)
i just divide by common factors first step
numerator 5a + 5b to 5 ( a+b)
then denominator 2d (d + 1)
then i just divided both numerator and denominator by common factors (a+b) and d
so i got the answer 5 / 2 (d + 1)
how would you guys solve it? sorry if my reasoning bit over the place, any chance you can show me your working so i can aware myself.
thank you.
#49 Re: Help Me ! » algebra reducing fractions to lowest terms » 2013-07-08 10:55:24
thanks i will save thread and look over it again so i dont forget ^^
#50 Re: Help Me ! » algebra reducing fractions to lowest terms » 2013-07-08 10:46:23
(y + 5)(y - 3) / (2y - 6)(y - 3)
so answer
(y + 5) / (2y - 6)
but the denominator can be factored further to 2 (y - 3)
so answer is (y + 5) / 2 ( y- 3)
bah is my logic correct or is there something missing S: