algebra reducing fractions to lowest terms

bronxsystem · 2013-07-08 10:40:49

Hey all im stuck on this problem and looks like i will need to redo the chapter because im missing something.

Any chance someone can just aware me how to solve this?

Reduce the following fractions to lowest terms

(y^2 + 2y - 15) / ( 2y^2 - 12y + 18)

been up a while my brain all mushy but i know im meant to factor both the numerator and denominator into their prime factors.

i think the denominator would be (2y - 6) (y - 3) is that right?
the numerator im stuck and not sure what to do next

any help appreciated ^^

Last edited by bronxsystem (2013-07-08 10:48:06)

bronxsystem · 2013-07-08 10:46:23

(y + 5)(y - 3) / (2y - 6)(y - 3)

so answer

(y + 5) / (2y - 6)

but the denominator can be factored further to 2 (y - 3)

so answer is (y + 5) / 2 ( y- 3)

bah is my logic correct or is there something missing S:

Last edited by bronxsystem (2013-07-08 10:55:04)

bobbym · 2013-07-08 10:50:22

Hi;

You will be able to finish now.

bronxsystem · 2013-07-08 10:55:24

thanks i will save thread and look over it again so i dont forget ^^

bobbym · 2013-07-08 10:57:35

If you get stuck factoring numerator and denominator then use the quadratic formula on them.

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