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#26 Re: Help Me ! » Adding tax+commisions to get final price » 2013-01-06 08:21:25

Good going!

You are quite welcome!  I'm glad you got it worked out.  To work algebra word problems I usually
start by guessing at the answer.  Then in working to see if it's the right guess I keep track step by
step as to how I determine whether it is correct or not.  There is usually a step where something is
supposed to equal something else.  If it does then the guess was correct.  If not then putting a
brand x generic guess where the original numeric guess was and going through the same steps,
the equation to be solved shows up where the "they were not equal" occurred.

There are several advantages to this approach.  1)  Anyone can make a guess and so can get
started on working the problem.  2)  The guess doesn't usually even have to be reasonable.
3)  After the guess, there is no information left out so one can reason through the problem in
the manner they are used to dealing with this type of problem.  4)  If one can't determine whether
or not the guess is correct they they probably don't understand the background material or the
problem is not well stated.  5)  If one does determine that the guess is correct then they have
the answer.  6)  If the guess is incorrect then they are very close to having the equation to be
solved (equality involving the generic guess x following steps for guesses) .  7)  Sometimes
after finding that a guess is wrong it is easy to adjust the guess to get the right answer.

The main advantage is probably that one is able to work out the steps in the "usual" manner
instead of having to work in a strange direction dictated by the "missing part" being looked for.
The "usual" manner leads to the equation to be solved.  Then solving the equation is straight
forward which alleviates one from having to work through the problem from a "strange"
direction.

This approach was "driven home" to me when I ran across a "heads of lettuce" problem in an
algebra book.  I had never seen anything like it before and so had no "standard approach" to
work with.  So I took a guess, worked through it (it was a wrong guess) and tried several
revised guesses.  They didn't work either, but I knew I was reasoning through the problem
correctly.  So putting the "generic" guess x in instead of the specific guesses and going through
the SAME steps, the equation to be solved popped up.  Solving it was a breeze.  That made me
acutely aware of the method mentioned. 

An in case you wonder whether guessing is a "valid" approach in mathematics, just know that
there are many places in mathematics that the "official" technique for solving (differential
equations, for example) is to "guess and correct, estimate and revise" or whatever they may
wish to call it.  It is probably the most common way that human beings learn things.  We guess
and if it doesn't work we guess and try again.  We learned to crawl, walk, ride a bike, drive a car,
etc. by this approach.  Much of mathematics is obtained by observing patterns and then guessing
what equation for formula "fits" the patterns.

Well, I didn't intend to write a book here.  I get a bit verbose at times.  But I hope this will be of
help to you.

Have a super day today! smile

#27 Re: Help Me ! » Adding tax+commisions to get final price » 2013-01-05 05:09:44

Hi nimsun!

Let C=Cost,    M=Margin,    DC=Dealer Commission,    SC=Salesman Commission,    T=Tax.
From your simple math calculation of 116.5 I see that you are calculating the DC, SC and T on
the total C+M, which we can call A; that is, let A=C+M=100.

Let R be the Dealer Commission RATE (which is given as 10%).

Your "working backwards" appears to involve only the DC and the total 116.5 and LEAVES OUT
the SC and the T.

The complete equation from your simple math is

                  (C+M) +  SC  +  DC  +   T    = total = 116.5  which is
                      A    + .02A + .10A +.045A = A+.165A = 1.165A = 1.165*100 = 116.5 

Then working backwards (solving for R given the total 116.5) replacing DC by R*A we obtain

       A  +   .02A    + R*A +    .045A
= 100 + .02(100) + R*A + .045(100)
= R*A+106.5

But this R*A+106.5 is the total 116.5; that is, R*A+106.5=116.5  so  R*A = 10.

Thus R*A = R*100 = 10  yields  R=10/100 = .10 = 10%

( .10A = 10 yields A = 100 which checks.)

This is one advantage of using algebra.  Give the unknown a name (here R) and write the equation
from the "simple math" approach.  Then solve for the unknown.  This allows us to get the
necessary equation reasoning from our "simple math" approach.

Have a very blessed day and New Year!  smile

#28 Re: Dark Discussions at Cafe Infinity » Happy 2013 » 2013-01-04 09:53:04

Thanks!  So for 2013, 2014 and 2015, 2013=abc, 2014=def, and 2015=ghi where the nine letters
represent nine different prime integers.  smile

#29 Re: Dark Discussions at Cafe Infinity » Happy 2013 » 2013-01-03 10:51:35

Hi pellerinb!

I don't understand what you mean y "each with unique factors" for the consecutive numbers
(necessarily odd since if even they would have 2 in common).  Any two consecutive odd integers
must have no factors in common other than 1 since the difference of the two (larger less smaller)
is 2.  This means the only possible common factors are 2 and 1 and certainly 2 is not a common
factor for these odd integers.

Please clarify. smile

#30 Re: Maths Is Fun - Suggestions and Comments » Title of Insane Member » 2013-01-03 06:00:50

Perhaps Summa as in "Summa cum laude."  Or maybe Laudy as in "Laudy how come?"
Or maybe "Over 25" or "Over the hill gang."  Or maybe "Survivor." ... smile...:)...:)...

#31 Re: Introductions » Greetings from "digits" the dyscalculic savant » 2013-01-02 14:35:16

Hi digits! smile

Math is not so much a matter of grey matter as it is a question of language --- symbolism,
definitions, algorithms, notation, etc.  It was created over a period of thousands of years by folks
that couldn't communicate together (like we are blessed to be able to do in this present age) and
so we have a hodgepodge of language which is often redundant, misleading, cumbersome, harder
to manipulate than necessary and at times just plain wrong.  Not to mention that mathematicians
often disagree on notation, definitions, concepts etc.

Most folks are led to believe that math is as near perfect as anything that mankind has created.
Consequently they usually blame themselves ultimately when they have trouble with math.
Unlike the sciences where theories come and go math is based on logic, definitions, axioms,
theorems, algorithms, etc.  So what could possibly go wrong?  Hint:  It was created by human
beings.   

Since you and your husband both are interested in math you might google "math the original four
letter word" and enjoy some of the sites that pop up.  Some of the sites point out some of the
problems with the language of mathematics.

But of course it doesn't hurt to have great intellect, a photographic memory, lots of creativity, etc.
for doing mathematics.  It is just that most of us are not "giants" like Gauss, Euler, von Neuman,
etc.''  I've always had to work hard to understand mathematics (at least the small part of it that
I know).

Have a very blessed year this year!  smile

#33 Re: Euler Avenue » Ramanujan's pi approximation equation » 2013-01-02 13:54:12

Not quite as accurate but easy to remember:  Studder quoting the first three odd positive integers
1 1 3 3 5 5 and divide the 113 into the 355 to get 3.141593 accurate to 7 significant figures.

                    3. 1 4 1 5 9 2 9 ...
             ____________________  rounds to 3.141593  same as 3.14159265... does.
    1 1 3 | 3 5 5. 0 0 0 0 0 0 0 0 0

smile

#34 Re: Maths Is Fun - Suggestions and Comments » Second Derivative » 2013-01-01 08:51:33

Thanks bobbym, smile

I used copy and paste to put Plot[{x^3,D(x^3,x),D(D(x^3,x),x)},{x,-5,5}] into the input instead of
the differentiate command and it plotted all three.  So that site does much more than just differentiate.  Neat!

#35 Re: Puzzles and Games » Logarithm game! » 2013-01-01 08:37:55

julianthemath,  Have you see the fact that

  logy       logx
x        = y         which is still true for any positive base b (not 1) and positive x and y? 

One might get some interesting variations on these log problems using this fact.

#36 Re: Maths Is Fun - Suggestions and Comments » Second Derivative » 2013-01-01 08:22:17

That's nice and a good site to remember.  It only lacks a graph of f, f' and f'' on the same set of
axes.

#37 Re: Puzzles and Games » 2 primes that equal » 2013-01-01 08:01:59

1997-197 = 1000

Oops!  Off to a great start for the new year I am!

Should have been 1997-997. smile

#38 Re: Maths Is Fun - Suggestions and Comments » Second Derivative » 2013-01-01 07:56:52

It would be nice to have a link to a calculator that can calculate these derivatives for the common functions and graph f, f' and f'' in different colors on the same set of axes.

I think such programs exist, but are probably part of a larger program or are not free.  A simple
free link to a program that just does the derivatives and graphing would be nice.

#41 Re: Coder's Corner » Welcome to Coder's Corner » 2012-12-28 14:29:25

When Al Gore goes jogging his pace is called an algorithm.  And if he runs across fallen tree trunks
then it is also a ...  But it is difficult for him if the logs don't line up nicely.  So maybe an algorithm
can be a missfelled logarithm, eh mikau?

#42 Re: Euler Avenue » Wilson's Theorem » 2012-12-22 05:16:40

Wiki has a proof for Wilson's Theorem (Google Wilson's Theorem Proof).  To follow it one must know
a good bit of number theory.  I am not a number theorist so it refers to things I am not familiar with.
That's why I look at the problem the way I did in my previous post.  Maybe someone else can explain
the number theory congruence bit for you.

Good luck! smile

#43 Re: Help Me ! » Creating Functions? » 2012-12-21 16:57:38

One approach:  Work out lots of cases and examples and look for patterns that can be turned into
formulas.  Nowadays it is lots easier to do with the aid of computers that can run out cases by the
bucket load. 

Anybody else care to contribute your favorite methods?

smile

#44 Re: Euler Avenue » Wilson's Theorem » 2012-12-20 17:05:45

Wolfram Mathworld  explains:

(p-1)!+1 is a multiple of p, that is (p-1)!=-1 (mod p) if and only if (iff) p is prime.
On the other hand for a composite number n, (n-1)!=0 (mod n) except when n=4.
.....................................................................................................................
   
BUT
Fermat's little theorem is a better way to determine primality since Wilson's theorem involves
factorials which are extremely large for even relatively small values of p.  For example to test
71 for primality we would have to do 70!/71 with 70! being larger than 10^100.

It may be easier to understand the concept in terms of quotients.

Except for n=4, IF n is COMPOSITE then (n-1)! must contain in its list 1*2*3*...*(n-1) a pair of factors of n strictly between 1 and n.  Example:  If n=6 then 5! = 1*2*3*4*5 has  2 and 3 as factors of 6.  Hence if we divide 6 into 5! we get an integer for the quotient. 

On the other hand if p is prime then (n-1)! will have no factor of n except 1.  Hence, the
quotient (n-1)!/n will not be integral.

Hence for any integer n>1 and not equal to 4, n is prime iff (n-1)!/n is not an integer
                                                            and  n is composite iff (n-1)!/n is an integer.
n=4 is a special case since the only factor of 4 strictly between 1 and 4 is 2.  Hence 3!/4 is not
an integer.  Note that 9=3*3 but in the list 1*2*3*4*5*6*7*8 we have two factors of 3, one is 3
itself and the other is a factor of 6.  Hence 8!/9 will be integral; that is, 8!/9 = 2*4*5*2*7*8.

smile

#45 Re: Help Me ! » binomial » 2012-12-20 16:11:44

I'm getting the same as bobbym.  It sometimes helps to write the original function in terms of
a different variable than the one you are substituting in its place.  For example

f(x) = x^3+6x^2+12x+8 = x^3 + 2*3x^2 + 4*3x + 8 = (x+2)^3

f(x) = (x+2)^3 so f(t-1) = ((t-1)+2)^3 = (t+1)^3 = t^3+3t^2+3t+1 = (1, 3, 3, 1) by replacing
x by t-1 in the f(x) = (x+2)^3.

And as another example find the quadruple for f(t-2).

f(x) = (x+2)^3 so f(t-2) = ((t-2)+2)^3 = t^3 = (3, 0, 0, 0). 

These can also be looked at as a composition of functions: f(x)=(x+2)^3 and g(x)=x-1.

(fog)(x) = f(g(x)) = f(x-1) = ( (x-1)+2)^3 = (x+1)^3  smile

#46 Re: Puzzles and Games » Sum of 3 digits and its compliment to 1000 » 2012-12-18 03:57:01

And if casting out nines on the sum of the two complementary numbers, the result will still always
be one. 

Does anyone use casting out nines anymore? smile

#47 Re: Help Me ! » Cannibals » 2012-12-17 18:33:59

Of course this is all assuming that the guys aren't freaked out and can figure out what's going on.
The back guy and middle guy might be unable to think under the pressure and so just say "I don't
know".  But then at least one of them must guess, so they have at least a 50/50 chance! smile  I'm
not sure I could think under those circumstances!

#48 Re: Exercises » Who knows a formula of Pythagorean numbers? » 2012-12-17 18:17:20

Join the club!  Mine doesn't work well late at night either. smile

#49 Re: Maths Is Fun - Suggestions and Comments » Science Website Names » 2012-12-17 17:51:03

I googled "scienceisfun.com and got no hits.  I did get a hit on "scienceisfun.org for a 7th grade
teacher Linda Smith.  On Yahoo I got a hit on "scienceisfun.com" but it just opened up a page of
ads.  So might "scienceisfunforum.com still be a possibility? smile

#50 Re: Puzzles and Games » guess the combination number! » 2012-12-17 17:30:48

1) Iowa
2) Alabama
3) Texas

smile

Edit:  Of course London and Paris are also in Texas!

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