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#26 Re: Help Me ! » Help with Delta-Epsilon proof for sinx. » 2008-02-12 15:09:00

Actually... To show what I have done:

I found that

And that:

And then plug in that for the first part... but I'm not sure how that would help!????

#27 Help Me ! » Help with Delta-Epsilon proof for sinx. » 2008-02-12 14:54:56

clooneyisagenius
Replies: 2

If i let f(x) = sinx. Find the error E(x, pi/2) in equation:
E(x,a) = f'(a) - [(f(x)-f(a))/(x-a)]
as a function of x.  Graph E(x,a). Find a delta if epsilon = .01, .0001, 10^-10.

Honestly I can do the graphing part.  I will also be able to do the proof when epsilon = .0001, 10^-10 once I have seen a proof for one part.  I am having a hard time with the teacher - he has yet to do an example of how to do one of these proofs... and the book, needless to say, is not much better.

Any help would be great.

#28 Help Me ! » Derivatives Help? » 2008-02-07 14:50:34

clooneyisagenius
Replies: 2

I'm working on some tougher derivatives.

1.

and

2.

, x is in the Reals


-----------------------------
For #1:
I tried to look at it two separate ways as x>0 and x<0.
I figured if x<0 then:

and thus

and if x>0 then:
and thus

Does this make sense? It seems too easy?

STUCK PRETTY MUCH COMPLETELY ON #2. hmm

#29 Help Me ! » Analysis Help... needed horribly! » 2008-02-03 15:57:30

clooneyisagenius
Replies: 1

I'm just wondering if there is a good book or place to get self help on Analysis stuff?   I learned calc I and II through these books but I'm trying to learn more for Analysis but am not sure where to get help or find a good book about it

#30 Re: Help Me ! » Intro to Analysis - Find target of series, etc. » 2008-01-29 16:41:42

AHA!

So, I know how to find that the target value is 4/7 (or .572193) now... (I THINK!)

I want to look at the geometric series:


and plug in
for x
which gives me:

Which equals 4/7! Thanks Ricky!

Now... to find the value of

so that any partial sum with at least
terms is within 0.001 of the target value.

#31 Help Me ! » Intro to Analysis - Find target of series, etc. » 2008-01-29 14:10:28

clooneyisagenius
Replies: 3

I need to:

Find the target of the series: 
1 - (3/4) + (9/16) - (27/64) + ... + (-1)^k*(3^k/4^k)
Then i need to find any value of n so that any partial sum with at least n terms is within 0.001 of the target value. Justify the answer.

So here's what I did. I made a program on Mathematica that gave me that the target value of the partial sum is .571429

I also found that at the sum from 0 to the 22nd term is equivalent to 0.572193

I suppose I have my answer but I cannot justify it - except using proof by mathematica program.  I am worried though that when I have an exam and am forced do this without mathematica I will not be able to.  Is there any advice? Or can someone teach me how to do this?

#32 Help Me ! » Construct a series that suggests that the sum? » 2008-01-27 10:04:57

clooneyisagenius
Replies: 1

I need to construct a series that suggests that the sum (of alternating 1’s and −1’s) is 1/4. Or 2/3.


Here's what was written in class before this:
Here is an example that seems to suggest that
1 − 1 + 1 − 1 + 1 − 1 ± · · · = 1/3
.
Consider the series
S = 1 − x + x3 − x4 + x6 − x7 ± · · · .
Note that
S = (1 − x)(1 + x3 + x6 + · · ·) = (1 − x)*(1/(1 − x^3)) = (1/(1 + x + x^2))
Evaluate at x = 1.

.......

I'm not even sure how the example works completely... let alone how to do one on my own.

#33 Re: Help Me ! » Series and partial sum... » 2008-01-24 17:23:41

Wow. I feel like it was just one of those problems where I went right past something that wouldn't have been that difficult to making the problem very difficult.  Thanks Jane.  I knew the answer was pi/3 but you've helped and made it completely clear!!

I had a similar problem to do and thanks to you I've already done it! You are a great help!

#34 Help Me ! » Series and partial sum... » 2008-01-24 16:30:51

clooneyisagenius
Replies: 3

Question: Prove that the partial sums are always greater than or equal to 1 once we have at least fiver terms.  What number does this series appear to approach?

Series: 1 + (1/5) - (1/7) - (1/11) + (1/13) + (1/17) - ...

I found that:
my.php?image=84280156ir3.jpg

But it is also given in the book that the sum is from k=1 to k with:

[(-1) ^ [Floor((k-1)/2)] ] / [6*(Floor(k/2)) + (-1)^(k-1)]  (sorry not being in code - i'll work on it but wanted to get this up)

Any ideas on where to go?

#35 Re: Help Me ! » Abstract Algebra Proof Help - Group Theory » 2007-12-17 05:16:27

Thanks. I also got number one. Thanks for you're help on 3, it pushed me to finishing one. Hopefully doing this problem on the practice exam I'll be able to do a similar one on the final. You've been a huge help.

#36 Re: Help Me ! » Abstract Algebra Proof Help - Group Theory » 2007-12-17 03:16:39

phi is the permutation.  but on #2 i meant phi(f) = f(1/4)

#37 Help Me ! » Abstract Algebra Proof Help - Group Theory » 2007-12-17 02:48:33

clooneyisagenius
Replies: 5

Let G be the set of all real-valued functions on the interval [0,1]. Define f+g for f,g in G by (f+g)(x)=f(x)+g(x).

1. Prove that G is a group
2. Define phi : G->R by phi(f)=phi(1/4) and prove that phi is a homomorphism
3. Let H={f in G such that f(1/4)=0}. Prove H is a subgroup of G.
4. What is G/H isomorphic to?

All in all - just stuck. Any ideas?

My work so far:
G is a group means that it is assosciative, closed, has an inverse and identity. (It's associative because addition is)

#38 Help Me ! » Neutral Geometry » 2007-12-15 09:51:13

clooneyisagenius
Replies: 1

Need some help in neutral geometry.

The first one is to prove that parallelograms exist.

(the others depend on this proof so hopefully getting this will help me do those) I started by using a saccheri quadrilateral and using triangle congruences to prove it but i get stuck.

Thanks -

#39 Help Me ! » geometry help (2 questions) » 2007-10-15 03:13:33

clooneyisagenius
Replies: 0

1. Given 3 non-collinear points, there is one and only one circle containing all three points.
2. If triangles ABC and DEF have right angles at A and D and have AB=DE and BC=EF show the triangles are congruent.


For 1: The three points are on the circle.  I'm not sure where to start. We've really only done work with triangles and lines in the class so far.
For 2: I now have angle-side-side which is not a valid form of proof. I've tried proving by contradiction with no success.  I'm not sure what step to take now.

ideas?

#40 Help Me ! » college geometry help with proofs? » 2007-10-01 14:05:50

clooneyisagenius
Replies: 4

1. Prove no line can intersect a circle more than twice.
2. Assume that any straight line drawn from a point on the circle to a point inside will intersect the circle at least one more time. Prove that it will intersect the circle exactly once more.


for 1... I did it using Pasch's postulate but now the prof. wants us to do it again with a different method and I just haven't figured it. I have 3 pages of drawings and attempts but it's due tomorrow now... and the past week I've yet to figure it out???

and for 2 i feel like i need to use the fact that "no 3 lines can intercept a line from a point such that all lines have the same length" [which i've proved in this same problem set].

Ideas?

#41 Help Me ! » odd permutations form a group...identity » 2007-09-27 11:12:37

clooneyisagenius
Replies: 4

Do the odd permutations of S_n form a group? Explain.

I KNOW that they dont for the reason that the group of odd permutations does not include the identity. I'm not sure how to prove this in general.

Thanks.

#42 Help Me ! » Subgroups of a Set // Abstract Algebra » 2007-09-13 10:52:58

clooneyisagenius
Replies: 2

Let Q be the group of rational numbers under addition and let Q* be the group of nonzero rational numbers under multiplication. In Q, list the elements in <1/2>. In Q*, list the elements in <1/2>. Find order of each element in Q and in Q*.

I know that....
for any element, a, from a group, G, we let <a> denote the set {a^n l n in Z}. I've finished other problems dealing with this but this problem is fooling me. hmm

Thanks.

#43 Help Me ! » dihedral symmetry - rotation / reflection? » 2007-09-03 11:16:25

clooneyisagenius
Replies: 2

1. What are the symmetries of a nonsquare rectangle?
2. What are the symmetries of a parallelogram that is neither a rectangle or a rhombus.
3. What are the symmetries of a rhombus that is not a rectangle?

My thoughts:
1. 4: The identity, 180 degree rotation, vertical reflection and horizontal refletion?
2. 4: The identity, 180 degree rotation, 2 reflections from opposite angles.
3. 4: same as above?

it doesn't seem right because 2 and 3 seems like they shouldn't be the same? THOUGHTS? Thanks.

#44 Help Me ! » Pigeonhole Problem... » 2007-04-22 05:53:46

clooneyisagenius
Replies: 0

The Question: If S is a subset of {1,2,...,n} having size 2n+1 prove S contains 3 consecutive numbers. Show that this is best possible by exhibiting a set of size 2n for which the conclusion is false.

My Answer:  Suppose S has no consecutive elements, and label its elements k(0), k(1), ..., k(2n - 1), k(2n) in order, so that
k(0) < k(1) < ... < k(2n - 1) < k(2n).

Since these aren't consecutive, we have that k(i) - k(i - 1) ≥ 2 for i = 1, 2, ..., 2n. Thus
k(2n) - k(0) ≥ [k(2n) - (k(2n - 1)] + [k(2n - 1) - k(2n -2)] + ... + (k(2) - k(1)) + (k(1) - k(0)) ≥ 2n * 2 = 4n.

Since the smallest k(0) can be is 1 and k(2n) can be no larger than 3n, it follows that  3n ≥ k(2n) ≥ k(0) + 4n = 4n + 1, which is contradiction. Hence S must contain some consecutive elements.

I need to use the pigeonhole principle in my answer (says the teacher). I'm not sure how I can use it in this case. I thought i did, but.... Any ideas??

#45 Re: Help Me ! » 3 discrete math problems: 1. countable sets, 2. probability, 3. pascal » 2007-04-10 10:38:00

Thanks everyone, I got #3; and got it correct on the test! smile

#1 I got wrong, I attempted to not directly copy anyones work here, but instead tried to use advice from different posts and I was wrong and have to try and fix it now, but I appreciate all the help.


I didn't actually understand #2 really until WHATISMATH posted.  I appreciate it

Thanks for the help everyone.

#46 Re: Help Me ! » Test Coming Up.... Help? » 2007-04-10 07:44:51

Ricky - I didn't have another example to ask the question for. Sorry, but I still dont understand anyone's answers.

2. Lattice path - as my book says - A lattice path in the plan is a path joining together integer points via steps of unit legth rightward and upward. Typically the rightward is given a value of 1 and the upward is given a value of 0.  If given a path from (0,0) to (0,1) to (1,1) to (2,1) to (2,2) I understand the path will be (1,0,0,1) but after that I'm not sure what good they are? What's their use?

Cardinatlity - I guess what the point is?

#47 Help Me ! » Test Coming Up.... Help? » 2007-04-10 07:02:09

clooneyisagenius
Replies: 2

Some things I'm confused about:
1. How to show that the union of countable sets is also countable. For example, let A1, A2, ... be a sequence of sets, each countable. How to prove the union is a countable set.

2. What the use of lattice paths is. I understand how to make/get one... by I'm not sure how, on the test for example, it could be used in a problem.

3. How to count something in 2 ways

4. Cardinality.

and
5. Binary coding / n-tuples. For example, our teacher emailed us today with a question he says we should be able to answer easily: The 51st State of the union is going to be the State of Tom.  I will be
issuing license plates for cars using 3 letters from the alphabet.  How many plates can I make?  In essence we are counting ?-ary ?-tuples.  Finally, what is the probability that a randomly made plate will spell Tom?

ANY ADVICE/HELP WOULD BE WONDERFUL.

#49 Help Me ! » Proof finished...(need explanation w/1 thing) & help on summing cubes? » 2007-04-08 14:47:17

clooneyisagenius
Replies: 3

1. Need to Use Pascal's Formula and induction on n to prove the Binomial Theorem:
(DONT UNDERSTAND THE PART IN BOLD) Correct otherwise??

Base Case:  (a+b)^0 = 1 = \sum_{k=0}^0 { 0 \choose k } a^{0-k}b^k.
For the inductive step, assume the theorem holds when the exponent is m. Then for n = m + 1
(a+b)^{m+1} = a(a+b)^m + b(a+b)^m \,

= a \sum_{k=0}^m { m \choose k } a^{m-k} b^k + b \sum_{j=0}^m { m \choose j } a^{m-j} b^j by the inductive hypothesis
= \sum_{k=0}^m { m \choose k } a^{m-k+1} b^k + \sum_{j=0}^m { m \choose j } a^{m-j} b^{j+1} by multiplying through by a and b
= a^{m+1} + \sum_{k=1}^m { m \choose k } a^{m-k+1} b^k + \sum_{j=0}^m { m \choose j } a^{m-j} b^{j+1} by pulling out the k = 0 term
= a^{m+1} + \sum_{k=1}^m { m \choose k } a^{m-k+1} b^k + \sum_{k=1}^{m+1} { m \choose k-1 }a^{m-k+1}b^{k} by letting j = k − 1

= a^{m+1} + \sum_{k=1}^m { m \choose k } a^{m-k+1}b^k + \sum_{k=1}^{m} { m \choose k-1 }a^{m+1-k}b^{k} + b^{m+1} by pulling out the k = m + 1 term from the RHS
= a^{m+1} + b^{m+1} + \sum_{k=1}^m \left[ { m \choose k } + { m \choose k-1 } \right] a^{m+1-k}b^k by combining the sums
= a^{m+1} + b^{m+1} + \sum_{k=1}^m { m+1 \choose k } a^{m+1-k}b^k from Pascal's rule
= \sum_{k=0}^{m+1} { m+1 \choose k } a^{m+1-k}b^k by adding in the m + 1 terms.


2. Summing the cubes?
a)Prove directly that m^3=6(m choose 3)+6(m choose 2)+m
b)Use part (a) to prove that the sum(from i=1 to n) i^3 = [(n(n+1)/2]^2.(without using induction)
c)Prove part (a) by counting a set in two ways (hint: Count the ordered triples that can be formed from [m].)

Really just not sure where to go here... maybe some hint may help? I think I can do it... not sure where to start?

#50 Re: Help Me ! » Summation help. » 2007-04-05 15:41:27

Yes you are right pi man... I made a mistake... In my notes i did write 3^k... Made an accident here.  But I see what you are saying with:

pi man wrote:


∑(n choose k)*(3^n) :: (sum from k=0 to n)

But I think that it will be
∑(n choose 2k)*(3^n) :: (sum from k=0 to n/2)

and then divide that by 6^n to get .5?

what

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