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#26 Help Me ! » word problem » 2007-02-10 00:52:21

jxharmon
Replies: 1

sally bought 3 candy bars and a pack of gum for $1.75; jake bought 2candy bars and four packs of gum for $2.00 find the cost of a candy bar and the cost of a pack of gum?

5 candy bars and 5 packs of gum = 3.75
5x +5y=3.75 and now I am stumped;
5x=-5y+375Help me please

#27 Re: Help Me ! » rewrite as function of x Help! » 2007-02-10 00:47:07

My answers include f(x)=2/3x+2; f(x)= 3/2x-3; f(x)=3/2x-6; and f(x)=2/3x+6 so would my answer then be f(x)=2/3x+2?

#29 Help Me ! » rewrite as function of x Help! » 2007-02-09 03:24:03

jxharmon
Replies: 6

2x - 3y=-6
am I right in thinking that it would be f(x) = 3/2x-6

#30 Help Me ! » Need 2nd set of eyes to check plz » 2007-02-07 02:38:28

jxharmon
Replies: 2

10x+2y=7
Y=-5x+3
10x+2(-5x+3)=7
10x-10x+6=7
No solution


I am to solve the system by using either addition or substitution.

If a unique solution does not exist, state whether the system is dependent or inconsistent, this is where I am confused?????????????????

#31 Help Me ! » Double check on word problem..plz » 2007-02-06 15:35:02

jxharmon
Replies: 2

coffee beans sell for $9 per pd and $12 pe4r pd; the 2 are mixed to create 100 pds that sell for $11.25 per pd;
how much of each type will be used?

x(beans sold @$9 pd) + y(beans sold @$12 pd)=100
9(12y+100)+12y=1125
108y+900+12y=1125
120y+900=1125
120y=1125-900
120y=225
What am I missing???
x=25 pds, y=75 pds

#32 Re: Help Me ! » solve system by substitution » 2007-02-03 13:13:46

Thanks I thought I had totally lost it  I appreciate all the help

#33 Help Me ! » solve system by substitution » 2007-02-03 06:56:41

jxharmon
Replies: 2

I am having trouble with this:  it is to be solved by subsitition 4x-12y=5; -x+3y=-1

4(-3y + 1) -12 y = 5; -12y +4 -12y =5;  24y +4 =5  24y= -4+5; 24y=1 y=1/24 am I doing this right??

#34 Re: Help Me ! » number problem » 2007-02-02 15:21:58

thanks a million I could not figure out what I was doin wrong but I got it now
5n-5n+10d-5d=350-5*50; 5d=350-250;5d=100; d=20 so n+20=50; n=50-20=30; now I have n=30 and d=20 for a total of 50 coins and 5*30=150 and 10*20=200 for 350 in cash.

#35 Help Me ! » number problem » 2007-02-02 12:48:47

jxharmon
Replies: 2

have $3.50 in nickels and dimes; total 50 coins how many of each

n + d =50                 
5n + 10d = 350                                       
5 d = 35
d= -5 + 35=30
n + 30 = 50
n=20

20 + 30 = 50

5(20) + 10(30)= 100 +  300 = $4.00
what do I have to change to get $3.50? dunno they should have been just the opposite

#37 Help Me ! » solve and graph linear inequalities » 2007-02-02 05:55:25

jxharmon
Replies: 2

solve each of the following systems of linear inequalities graphically
3x-y<=6 ; x>=1 ; y<=3  if you do 3x - 0 =6 then 3x=6 and x<=2; and 3(1) - y(-3) =6 3+3=6; so you would graph (2,0) and (1,-3) but then on x>=1 you would put that at 1 on the x axis; and for y<=3 you would put that on the 3 of the y axis. is that the correct way to solve this problem??what

#38 Re: Help Me ! » geometry help! » 2007-02-02 05:23:48

Thanks guess I just got lost but it makes sense now.

#39 Help Me ! » geometry help! » 2007-02-02 04:23:20

jxharmon
Replies: 2

length of a rectangle is 2 inches mor than twice its width. if the perimeter of the rectangle is 34 inches find the demensiions of the rectangle; 2(length +width) =34; 2(2+2x)+x=34; 4+6x=34;6x=30; x=5 if that is right I am now beside myself in other words I am lost as to how to find the solutiondunno

#41 Help Me ! » stumped on addition again please help » 2007-02-02 03:49:27

jxharmon
Replies: 2

solve systems by addition
x+5y=10 and -2x -10y=-20 so if multiply the first equation by 2 I get 2x+10y=20 to me that would cancel out the other equation I'm so lost????

#42 Re: Help Me ! » solve system by addition » 2007-02-02 03:34:38

thanks I guess I just overlook the minus great help from both

#43 Help Me ! » solve system by addition » 2007-02-02 02:41:17

jxharmon
Replies: 3

2x+3y=1 and 5x+3y=16 state whether incon sistent or dependent; if I multiply the first equation by -1, Iget -2x-3y=-1 which means x=5 but then when I plug that into 5(5) +3y=16; 25+3y=16; 3y=-25+16; 3y=9;y=3   2(5) +3(3) =1 10 +9=1?   5(5) +3(3)=16 25+9=16 what am I doing wrong?

#45 Re: Help Me ! » HELP please....Business & Finance » 2007-02-01 03:56:36

OK...can you double check me?

a) -2,500
b) 4,250
c) not sure but here is how I worked it:

2.25x-7000=0
+7000          +7000
2.25x=-7,000/2.25
      x= -3,111

#47 Re: Help Me ! » HELP please....Business & Finance » 2007-01-31 04:03:16

can you do one of a, b, or c for an example...please

#48 Re: Help Me ! » Can u explain Function Notation » 2007-01-31 04:01:17

Great, thanks for all the responses...you guys are great!

#49 Help Me ! » HELP please....Business & Finance » 2007-01-31 02:09:52

jxharmon
Replies: 7

An inventor of a new product believes that the cost of producing the product is given by the function C(x) = 1.75x + 7000.

If the inventor charges $4 per unit, then her profit for producing and selling x units is given by the function P(x) = 2.25x - 7000

a) What is her profit if she sells 2000 units?
b) What is her profit if she sells 5000 units?
c) What is the break-even point for sales?

How do I work a,b, and c?

#50 Re: Help Me ! » How to make up an equation » 2007-01-30 02:03:01

Ok...that really confuses me. That means there would be 19 accidents estimated for 2007????

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