Math Is Fun Forum

jxharmon

Member

Registered: 2007-01-08

Posts: 104

geometry help!

length of a rectangle is 2 inches mor than twice its width. if the perimeter of the rectangle is 34 inches find the demensiions of the rectangle; 2(length +width) =34; 2(2+2x)+x=34; 4+6x=34;6x=30; x=5 if that is right I am now beside myself in other words I am lost as to how to find the solution

pi man

Member

Registered: 2006-07-06

Posts: 251

Re: geometry help!

You're doing great.   X is your width so your rectangle has a width of 5 and a lenght of 2 + 2X = 12.    To doublecheck: 2 times the width + 2 times the lenght = 2*5 + 2*12 = 10+24 =34.

By the way, there's one mistake in your equations.   Since you came up with the right answer, it must have been a typo.  2(2+2x)+x=34 should be 2(2+2x)+2x=34

jxharmon

Member

Registered: 2007-01-08

Posts: 104

Re: geometry help!

Thanks guess I just got lost but it makes sense now.