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#76 Re: Introductions » hello » 2006-12-10 04:20:17
Oh hi.. thanks for the welcome Suha...
hmm almost same name odd isn't it.
well yes my real name is soha....
#77 Help Me ! » ellipse » 2006-12-07 11:34:13
- Kiran
- Replies: 13
consider the ellipse that has vertices at (0,5) ,(0,-5) and foci at (0,3) and (0,-3)
and write its equation in standard form.
#78 Help Me ! » Evaluate.....last step can you help me on it thnx » 2006-12-06 03:44:04
- Kiran
- Replies: 1
Csc^2(-750dg) + tan 495dg
csc > cosec
csc(x) = 1 / sin(x)
csc^2(-70) = 1/sin^2 (-70)
sin(-70) = -sin (70)
csc^2(-70) = 1/sin^2(70)
------------------------------------
tan(x) = tan(x-180)
tan(495) - tan(135) = tan(-45)
tan(-x) = -tan(x)
tan(-45) = -tan (45)
csc^2(-70) + tan(495) = [1/sin^2(70)] - tan(45)
csc^2(-70) + (-1) = [1/sin^2(70)] - 1
next?
#79 Re: Help Me ! » sketch the graph » 2006-12-06 03:40:04
oh i dont know sorry . does anyoone else know how to do this kinds of problem?
#80 Help Me ! » i need help » 2006-12-05 12:15:03
- Kiran
- Replies: 1
Write the first three of an artithmetic sequence whose first term is -8 and whose common difference is 4.
#81 Re: Help Me ! » Right or Wrong » 2006-12-04 03:04:09
ok i have 2 more questions to the top information:
"Let "p" represent "the area of rectangle ABCD is 50 square inches."
Let "q" represennt "the perimeter of rectangle ABCD is 30 inches."
Llet "r" represent "the length of rectangle ABCD is twice the width."
p = area of rectangle is 50sqin
q = perimeter of the rectangle is 30in
r = ength of the rectangle is twice width
These Are The Two Questions..again teach said it is wrong so what can i do now?
If rectangle ABCD is 9 inches long and 6 inches wide, what is the truth value of the disjunction q v ~p ?
I wrote :
q = 9
p = 6
~ p = -6
pv ~ q = 9 + (-6)
9 - 6
3 it is positive value
`````````````````````````````````````````````````````````````
Suppose rectangle ABCD is 12.5 inches ong and 4 inches wide. What is the truth vaue of the conditional p --> r ?
I wrote :
ength = p = 12.5
width = r = 4
12 is always greater than 4
p > r
12.5 > 4 is the true value
#82 Re: Help Me ! » Right or Wrong » 2006-12-04 03:00:09
ok thanks 
#83 Help Me ! » Right or Wrong » 2006-12-02 04:59:01
- Kiran
- Replies: 4
"Let "p" represent "the area of rectangle ABCD is 50 square inches."
Let "q" represennt "the perimeter of rectangle ABCD is 30 inches."
Llet "r" represent "the length of rectangle ABCD is twice the width."
p = area of rectangle is 50sqin
q = perimeter of the rectangle is 30in
r = ength of the rectangle is twice width
THEY ASKED THIS QUESTION:
Use symbols to represent the conjunction below:
THE AREA OF RECTANGE ABCD IS 50 SQUARE INCHES AND ITS LENGTH IS NOT TWICE ITS WIDTH.
I wrote:
p = area of the rectange ABCD is 50 sq in
v = and
r = length of the rectangle ABCD is twice the width
~r = length of the rectangle ABCD is not twice the width
pv~r "
Right or wrong?
if right than why did my teacher say its wrong?
#84 Help Me ! » did the problem but need help with the graph » 2006-12-01 05:31:31
- Kiran
- Replies: 1
consider the hyperbola 16x^2 - 4y^2 + 64 = 0
write this equation in standard form and give the coordinates of the vertices and the equations of the asymptotes. then graph.
16x^2 - 4y^2 = 64
16x^2 / 64 - 4y^2 / 64 = 1
x^2 / 0.25 - y^2 / 0.0625 = 1 < simplified
Let x = 0
y^2 / 0.25 - (0)^2 / 0.0625 = 1
y = +- 0.5
let y = 0
(0)^2 / 0.25 - x^2 / 0.0625 = 1
x = +- 0.25
now teh coordinates are :
(0,0.5) (0,-0.5)
(0.25,0) (-0.25,0)
Asymptotes :
y = 0.5/0.25 x
and
y = - 0.5/0.25 x
now how do you graph the coordinates ?
#85 Help Me ! » supervisor / workers » 2006-12-01 04:40:54
- Kiran
- Replies: 1
a supervisor can complete 18 jobs in 3 minutes
a worker can complete 24 jobs in 6 minutes
the worker began to work for 2 minutes and then the supervisor joins in to help
how long would it take them together to finish a total of 88 jobs?
#86 Help Me ! » simplify plz help » 2006-11-29 05:33:29
- Kiran
- Replies: 3
h^(5) r^(-7) + r^(-2) h^(3)
--------------------------------
h^(6) r^(-4)
#87 Help Me ! » Hexagon » 2006-11-28 09:40:38
- Kiran
- Replies: 1
the length of a side of a regular hexagon is 4cm
what is the radius of the circle that can be circumscribed about this hexagon?
#88 Re: Dark Discussions at Cafe Infinity » History; What's Your Favourite Era? » 2006-11-28 03:52:05
my fav is 21 century............advance in technology
#89 Re: Help Me ! » hi » 2006-11-28 03:49:22
ok so thank you
now the law of sines is
a/sinA
b/sinB
c/sinC
right
now if we want to find y
we have to say
18/sin125 = y/sin(25) ?
for x i got 10.9869713 which is 10.0
now my finding y is that the right way?
#90 Help Me ! » hi » 2006-11-27 08:12:45
- Kiran
- Replies: 4
ok in this i have a problem in my book..which i like for you to help me out with now if you can i will so like that .
ok the top of the obtuse if Mdegrees
the bottom point is 25degrees
and the middle is 125degrees
the hypotenuse is 18
and the opposite side is y
and the ajacent side is x
now i have to find
x
y
Mdegrees
i did
125degrees + 25degrees + Mdegrees = 180
150dg + Mdg = 180
180 - 150 = 30
Mdg = 30dg
right
now how to find y and x?
#91 Help Me ! » is this right way » 2006-11-27 07:26:06
- Kiran
- Replies: 5
factor
9x^(2n+3) + 18x^(5n+1)
i did
9*x^n*x^n*x^3 + 9 * 2 *x^n*x^n*x^n*x^n*x^n + x
correct so far?
#92 Re: Help Me ! » matrix dimensions » 2006-11-27 07:12:50
GUYSSSSSSSSSSSSSSSSSSSS help.
what to do ?
#93 Help Me ! » Help » 2006-11-27 03:38:35
- Kiran
- Replies: 1
solve the following equation if 0 <_ 0 < 2pi :
sin0 + 2sin^2 0 = 0
HELp
#94 Re: Dark Discussions at Cafe Infinity » Who is the Fan Of Cricket?? » 2006-11-27 02:14:27
hmm thats nice. rida
same as me Devante... i don't play cricket .. and donn't even know how to play
for me it looks hard. dont you think?
hey girls can play cricket? i saw one girl she played very goood.
#95 Re: Introductions » hi! (._"_.) » 2006-11-27 02:12:08
welcome Haruka
its late but still
#96 Re: Dark Discussions at Cafe Infinity » Who is the Fan Of Cricket?? » 2006-11-25 03:31:19
you all must be experts at cricket
#97 Re: Help Me ! » completed equation now what » 2006-11-24 07:36:02
ok now i got....
y - y = (-4/3)x - (3/4)x + (-10/3) + 1/2
y - y = (-2 1/12)x + (-2 5/6)
nowwwwwwwwwwww
#98 Re: Help Me ! » completed equation now what » 2006-11-24 07:22:01
If first line is y = (3/4)x - 1/2, then the
perpendicular line to that line is slope of minus 4/3.
So the equation of that line is y = (-4/3)x + b.
To find b, we sub in the points given above.
(5,2) is the point of interest.
So 2 = (-4/3)5 + b
2 = (-20/3) + b
2 + 20/3 = b
26/3 = b
I'm not checking my answer yet, so it could be wrong.
So y = (-4/3)x + 26/3
Now you can find the intersection of the two lines so you get the other point of interest, which is how far away from the original point, we will find out soon!
...
(-4/3 )5 = -6 2/3 plus 2 which makes it -4 2/3
so b = -4 2/3 or we can say -10/3
#99 Help Me ! » matrix dimensions » 2006-11-24 06:26:59
- Kiran
- Replies: 2
give the dimensions of teh following matrix :
[ ] < this is around teh whole numbers .. all of them get me ?
2 5 4 6 5 4 6 7 8
9 9 8 7 0 9 5 6 3
0 0 0 9 8 7 6 3 1
1 1 0 0 2 5 5 8 6
i think
4 * 9 ????????
4 rows and 9 columns
#100 Re: Dark Discussions at Cafe Infinity » Who is the Fan Of Cricket?? » 2006-11-24 06:22:02
you can bat with any hand i think....left or right..... rigght?