Math Is Fun Forum

Kiran

Member

Registered: 2006-11-15

Posts: 177

Evaluate.....last step can you help me on it thnx

Csc^2(-750dg) + tan 495dg

csc > cosec
csc(x) = 1 / sin(x)
csc^2(-70) = 1/sin^2 (-70)
sin(-70) = -sin (70)
csc^2(-70) = 1/sin^2(70)

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tan(x) = tan(x-180)
tan(495) - tan(135) = tan(-45)
tan(-x)  = -tan(x)
tan(-45) = -tan (45)

csc^2(-70) + tan(495) = [1/sin^2(70)] - tan(45)
csc^2(-70) + (-1) = [1/sin^2(70)] - 1
next?

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John E. Franklin

Member

Registered: 2005-08-29

Posts: 3,588

Re: Evaluate.....last step can you help me on it thnx

When you said:
tan(495) - tan(135) = tan(-45),
that's not right because 495 - 360 is 135, slope is -1 for tan495, just like tan 135, so difference is zero.

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