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Was he Korean?
If I understand the question correctly, Its not possible
7*7*7*7 (* is whatever operation you place, + - x /) , the result will always be a mutiple of 7
nope, but I guess it would be under the same principle as solving equalities?
moxiuming, please fully understand the concept of infinity......
0.999999.... is represented as, you can even consider it to be a expression which holds the value 1
As I said before ,
I think I could fix the f(h)/h thing
Ricky, is my proof under the same principle as your? it looks similar but I dont know if its legal, it goes like this
says that f is a homomorphism from the additive group of reals to the multiplicative group of positive reals. says that f is differentiable and hence continuous.The only continuous homomorphisms from
to are of the form where k is a real constant.
Ah so you can assume its e^kx ? no need to prove that?
need help with this, thx
I know its easy if you assume f(x) to be n^x, since f(a+b)=f(a)f(b), then find n to be e, but is that enough? I mean it doesnt seem general
I could only get this far
Oh, I overlooked something, I could find a formula for sequence z_i , ok, problem solved, tons of calculation indeed
I don't get everything you wrote, but I noticed that the 1st
fold is based off of 2 opposite corners, but the folds after
that probably are cutting the remaining angles in half.
So when I folded it, A1 folded 1st, then A3, then the A2.
Sort of like on a ruler, 1/2's the quarters, the eighths,
the sixteens, etc...
for example, The right triangle C_1 A_2 B is what I got when I folded the second page, making the DB of the second page lie on the A_1B, then I continue to fold the third page, I will get another right triangle C_2 A_3 B, the DB of the third page lies on A_2B..... I could fold infite right triangle in this way, I want to get the sum of these triangles
my apology if I am not clear enough
I was bored and started folding my book idly
then I started to think what's the sum of the triagles if I fold it like this
Then I started to find the sum
How do I finish it
The sum should be covergent
but the problem doesnt exist in this case, since cosx cant take 1, 1-cox cant be 0
click on the calculation other people wrote, you will be able to see the code
you could click on the LaTeX other people wrote to get the code
oops didnt know its to get the LCM lol , fixed
Well yes technically, but the sphere is so huge (and so has curvature so tiny) that the ceiling could reasonably be approximated as a plane.
I wouldn't think that you'd get such a massive discrepancy from the expected 360 degree sum just because the ceiling might be very very very slightly curved.
Hmm,you got a point... isn't that some kind of visual fallacy, then?
I dont think the resistant is to the same direction as the gravity. thereforce they must be of different sign regardless of the observer
ceiling is not a plane, its a fragment on a sphere, since it's parellel to the ground.
oh yea, my bad,sorry left limit = right limit...
its not continuous, x cant take the value 4
its true if you consider it to be a relativistic space. XD.
P(A)= 1/4?
P(B)= 25/34 ?
P(C)= 1/13?
havent done probability for a long time lol
Ah, thats clears up a lots. Thanks
I argued with my father about the 0.9999... question. It's , of course I believe it's equal to 1
I said 0.0000(infinty)1 is zero.
He said: consider this function 1/x (x>0). 1/x is not connect with x=0, you couldn't find the integration between [-1,1] directly, have to do it by parts, because its not continous, therefore it's not 0.
I said, the number isnt even a point on this function. Infinity is not number, you can't substitute in to the function and get that value.
He said, well, what's the least distant between the points on this function and x=0 , it's zero. It's not continuous and now it's continuous .
I think his thinking is obviously flawed, but I couldnt spell it out lol,help