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#101 Help Me ! » length L » 2006-10-17 03:41:36
- Neha
- Replies: 2
if one side of a triangle has a length of L and another with a length of 3L
express the AREA of this rectangle in terms in terms of L.
area of rectangle equals LW
length times width
so
#102 Re: Introductions » hi » 2006-10-17 03:39:20
ok i will 
#103 Help Me ! » Graph » 2006-10-16 02:38:40
- Neha
- Replies: 10
Graph the set on the real number line
number line goes form -7 to 7
#104 Re: Introductions » hi » 2006-10-16 02:36:18
Thanks ganesh and wizard for the welcome
#105 Re: Help Me ! » hello » 2006-10-16 02:35:15
yeah i could of done it this way...duhhhhhhh thanks
#106 Re: Help Me ! » equation of the line » 2006-10-16 02:33:56
cool
#107 Re: Help Me ! » hello » 2006-10-13 06:07:56
thank you all so very much i was doing it this way :
i tryed to do that.
i said that the striaght line has to 180 degrees.
so i put 180 = 4x or 2y or 2z...
but answers came out totally different from yours
#108 Re: Dark Discussions at Cafe Infinity » Languages; What Are Yours? » 2006-10-13 06:03:38
Just
click [img]and you'll have this come up
then just erase [/img]
leaving [img]and then paste teh link...teh url..
and after that
again click on [img]
u'll again have
now erase [img]leaving[/img]
now you would have
[img]link[/img]
and then submit
and ur image will come up
easy as that
#109 Help Me ! » hello » 2006-10-13 05:58:07
- Neha
- Replies: 6
Compute the values for x,y,and z
#110 Re: Help Me ! » column » 2006-10-13 05:52:07
that was good?
#111 Re: Help Me ! » simplify.. » 2006-10-13 05:47:29
thank you very much everyone = )
#112 Re: Introductions » hi » 2006-10-13 05:38:22
hey thanks for welcome
welcome to u also...hope u have a nice time here and same goes for ur friend
#113 Re: Jokes » Find your duplicate!!! » 2006-10-13 05:37:22
oh god devante
#114 Re: Introductions » hi » 2006-10-13 05:35:12
hmmmm
#115 Re: Help Me ! » solve square » 2006-10-13 05:32:11
if its 2
so it would be
2 +- 4
#116 Re: Help Me ! » solve square » 2006-10-13 05:08:54
thanks
but shouldnt it be
4 +- 8
--------
-8
then
-0.5 +- (-1)
#117 Help Me ! » simplify.. » 2006-10-13 05:06:04
- Neha
- Replies: 8
(sqrt(2) - y) (2 - sqrt(y) )
,,,,,,,,,,,,,,,
| |
(sqrt(2) - y) (2 - sqrt(y) )
| |
```````````
right?
then wht
#118 Re: Help Me ! » Log » 2006-10-13 04:52:41
Thank You So Very Much For Explaining
#119 Re: Help Me ! » solve square » 2006-10-13 04:35:54
just like this one :
x^2 - 4x - 12 = 0
use the quadratic formula
-(-4) +- sqrt ( (-4)^2 - 4(1)(-12) )
-------------------------------------
2(-4)
4 +- sqrt ((-16) - 4(-48))
--------------------------
-8
4 +- sqrt ( (-16) - (-48) ) >>>>>> sqrt ( -16 + 48)
------------------------------- --------------------
-8 -8
4 +- sqrt (64)
----------------
8
now what...thats it or we have to do more?
#120 Re: Help Me ! » Log » 2006-10-13 04:29:53
ok i get it...
like this:
Log1/3 N = -3
log1/3 / logN = -3
Log1/3 = -3logN
log1/3 log (N^-3)
1/3 = N^-3
ok here is where i am getting stuck....
______________________________________________________________
and for this problem also.
log1/3A=-4
log1/3 / logA = -4
log1/3 = -4LogA
log1/3 = log(a^-4)
1/3 = a^-4
stuck
How do i find the number ..if i have -4 or -3. ? ?:/
#121 Help Me ! » equation of the line » 2006-10-13 02:55:05
- Neha
- Replies: 2
find the equation of the line with slope of -3 and y-intercept of 4/9
m = -3
b = 4/9
y = -3x + 4/9
#122 Help Me ! » Log » 2006-10-13 02:46:00
- Neha
- Replies: 13
how do you do log problems?
such as this one:
solve:
log 125 = 3
b
#123 Help Me ! » undefined slope » 2006-10-13 02:44:26
- Neha
- Replies: 1
find the equation of a line that has an undefined slope and that passes through (2,4).
m = 0
b = 4
y = 0x + 4 
#124 Help Me ! » column » 2006-10-13 01:53:20
- Neha
- Replies: 16
A D
\\ /|
\ \ / |
\ \ / |
\ \ / |
\ \ / |
\ /\ |
\ / \ |
\/___ \|
B C
I know it looks so wrong but thats the only way i could do it.
Given that :
~ ~
AB = DC and AC = DB, write a two column proof to show that:
~
Triangle ABC = triangle DCB
so how you write the two column proof?
#125 Help Me ! » right? » 2006-10-13 01:44:32
- Neha
- Replies: 1
Evaluate:
3^0 4^-1
----------- x^-2 y^0 z^-4
4^2
If x = 2, y = 4, and z = 1
i did:
3^0 = 1
4^-1 = 0.25
4^2 = 16
x > 2^-2 = 0.25
y > 4^0 = 1
z > 1^-4 = 1
so then put that in
(1)(0.25)
----------- (0.25)(1)(1)
16
right so far?
0.25
----- 0.25
16
now
.........:/