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3 1\3 = 10/3
Also theres a rule that says that for limits that go to infinity in a polynomial you can ignore all the terms but the highest degree.
You multiply this limit by 1:
Ok got it.
For exam-taking purposes, how do you decide in which side to take the element approach? Does it depend if we are talking unions or intersections?
Prove:
So how do I prove the second one? They both make sense but im just unsure how to go on about the proof. Do I need to work from the right side?
@Luca
I looked on the back of the book and the answer they show is the same as your first attempt:
So since it shows both parts are subsets of each, they are equal.
@Daniel
Venn diagrams are not a tool to proof in Set Theory. Venn diagrams constitutes a way to visualize but you cannot prove anything with them.
I have to use an element-wise approach. So to prove two sets are equal you have to show they are subsets of each other. So:
How do I show that A is a subset of the left-hand side?
Franklin, is there any method to solve this polynomials of 3 degrees and higher?
Does your calculator have a "solve" function as the TI-89 does?
Oh thanks for pointing that out. I just took Daniel's answer for granted. So:
my TI-89 says x=1.75487766625 as the answer for the polynomial.
Solve.
The area of the square is 2. The area of the circle is pi. The ratio is 2/pi
Yes your right.
"He Replies ‘"
what are those codes?
Very simple. Just couldnt think of it ![]()
To be honest with you, I took geometry a long time ago. I found all the course to be mostly common sense but I forgot the names of the theorems.
Anyways, I did some googling and it is because of supplementary angles.
Theres actually a formula to figuring out the sum of the angles of a polygon:
180(n-2) where n is the sides of the polygon.
Which I see he/she used by doing 180(5-2) = 540.
Its ok.
But your right. If you have too much mistakes then it just makes it really hard to follow a discussion.
Anyways, please post what your teacher says as I'd like to know as well.
Your right. What do you need help with? Just checking if you were right?
Thanks Franklin.
If you want to find ADC you would say:
180 - (a + 60) = 180 - a - 60 = 120 - a
which is quite different from 180 - a + 60.
I will get thinking about the e^C in a sec. But I was going over your first post and you said that:
But isnt this wrong? Isnt:
Did you understand all I did? As I said, every step I took is backed up by geometrical theorems which I dont recall their names. I suppose you do?