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#126 Help Me ! » slope am i right » 2006-10-12 04:40:54

Neha
Replies: 1

find the slope of the line that passes through th epoints (1,4)and(-1,6)

i have to the same way in this problem liek they did in that example?



  Find the slope of the line that passes through the points (-3,5) and (-5,-8).
First find the slope:   m = y1 - y2 / x1 - x2

m = 5 - (-8)     13
     ----------- =---- = 6.5
       -3 - (-5)     2

Using either point:  (-3,5)
Remember the form:  y - y1 = m ( x - x1)
Substitute:  y - 5 = 6.5 ( x - (-3))
                  y - 5 = 6.5 (x + 3)  Ans.

#127 Re: Help Me ! » simplify......Help » 2006-10-12 04:31:27

the start looks a bit hard but the middle and end seem ot be very easy
thanks

#128 Re: Help Me ! » sum » 2006-10-12 03:57:20

oh ok .
that wasnt that hard as i thought it was thanks

#129 Re: Help Me ! » simplify......Help » 2006-10-12 03:55:05

no the way i wrote it thats how the problem is written.
r over 1 + 4
and 4 over u

#130 Help Me ! » simplify......Help » 2006-10-12 03:49:43

Neha
Replies: 8

3
-------------
2s + r
      ----------
      1 + 4
          ----
           u

HUHdunno

#131 Help Me ! » sum » 2006-10-12 03:47:54

Neha
Replies: 3

the sum of the digits of a two-digit counting number is 5.
when the digits are revversed , the number is27 greater than the original number.
what are the two numbers?

#134 Re: Introductions » hi » 2006-10-11 07:12:04

yeah right now i dont have calculus.sorry
seems like you like doing calculus

#135 Re: Introductions » hi » 2006-10-11 04:35:15

hi thanks for the welcome everyone
and yeah the book's title is advanced math but its mostly algebra geometry and mix

#136 Re: Help Me ! » solve square » 2006-10-11 04:34:03

Oh thanks alot for the help.
yeah that was a bit nasty i was checking in my book to see how tehy did it ...and then tryed the same way on this problem ...didnt work. i dont know why
anyways thanks smile

#137 Help Me ! » solve square » 2006-10-11 03:36:25

Neha
Replies: 10

solve by completing the square:

3x^2 + x = -5
subtract x form both sides...
hmm

#138 Re: Introductions » hi » 2006-10-11 03:34:31

Hi Patrick
math advanced math.

#139 Introductions » hi » 2006-10-11 03:31:18

Neha
Replies: 37

Hi all.
how are you i am new here. stuck in math would really like someone to help me. ok then see you bye

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