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I CANT SOLVE IT!!!@!@!
Mathematica gives something very ugly.
This may be of some help, although I don't see how the second line works...
http://au.answers.yahoo.com/question/index?qid=20080220024624AAoHR5q
Last edited by Daniel123 (2008-06-16 06:42:10)
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Here's another page working out that integral, that I think is clearer. (Thanks Jane!)
Both those pages deal with bounds of 0 and π/2 though, and I'm not sure how easy it would be to apply the methods to different bounds.
Why did the vector cross the road?
It wanted to be normal.
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i get 2*(pi^2)log(2)
I made the substitution z=exp(ix). it then reduces to a complex integration using a semicircle with radius one as the contour. i then construced the the power series and used the coeficient of 1/z as the residue.
not sure if there are any other singular points in the contour apart from z=0
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