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1. Prove that if a = an10n + an-110n-1 +
+ a110 + a0 is any positive integer then
a ≡ an + an-1 +
+ a1 + a0 (mod 9). [Note: 10 ≡ 1 (mod 9)]
2. Prove that the equation a2 + b2 = 3c2 has no solutions in nonzero integers a, b, and c.
[Consider the equation mod 4 and show that a, b and c would all have to be divisible by 2. Then each of a2, b2, c2 has a factor of
4 and by dividing through by 4 show that there would be a smaller set of solutions to the original equation. Iterate to reach a
contradiction]
3. Let n є Z, n > 1, and let a є Z with 1 ≤ a ≤ n. Prove if a and n are not relatively prime, there exists an integer b with 1 ≤ b < n such that ab ≡ 0 (mod n) and deduce that there cannot be an integer c such that ac ≡ 1(mod n).
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#1
Note that
for some integer K.
#3
Let p be a prime dividing both a and n and set
Last edited by JaneFairfax (2008-08-27 00:43:28)
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