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Q:1:- Prove that the function f(x)=x^3-2x+3 is continuous.
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See this thread.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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A function is countinous when lim(delta x--->0) delta y=0
f(x)=x^3-2x+3
SO lim(delta x--->0) (x+ delta x)^3 -2(x+delta x) +3 -x^3+2x-3=x^3+3[x^2]deltax+3x(delta x)^2 +(delta x)^3 -2x-2delta x +3-x^3+2x-3=3[x^2]deltax+3x(deltax)^2+(deltax)^3-2deltax=0
So this function is countinous
Last edited by G_Einstein (2008-11-12 02:50:36)
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