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choose 6 numbers from 49; with 100 tries. what is the chance of winning and why?
Correct me if i am wrong but I think this is the binomial distribution with:
N = 100
Probability for getting the number = 1/49
Define X is the number of winning number, then we have
Pr (X = 6) = 100C6 x 1/49^6 x 48/49^49-6 Where 100C6 = 100!/ 6! (100 - 6)!
With 1 try your chance of winning is 6/49 * 5/48 * 4/47 * 3/46 * 2/45 * 1/44 = 1/13983816. This means that your chances of not winning in 1 try are 13983815/13983816. Raise this number to the 100th power to find your chances of not winning in 100 tries, then subtract this number from 1 to find the chances of winning at least once in 100 tries. The final answer will be: 1 - (13983815/13983816)^100.
Wrap it in bacon
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I think you are correct. The Dude
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