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2∫tan³θdθ
and
∫( ( 2x+12 ) / (x³-4x) ) dx
first, the easier of the two integrals, using the result that:
we have:
for the other, we can do:
so we have in the end:
note: that since
you could also have:
since the -1 difference is constant and can be included in the C, you could argue using secant instead of tangent is the integral in a simpler form, since then it only really involves the functions cosine and logarithm.
Last edited by luca-deltodesco (2008-11-29 21:40:37)
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Last edited by luca-deltodesco (2008-11-29 23:17:04)
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thank you delco that helps me out alot
theres one thing i dont understand though, when you get to the substitution. why use the substitution if you can already find what ∫tanθsec²θdθ
it seems like you have ∫tanθsec²θdθ and use substitution to make it into tan²θ-∫tanθsec²θdθ
i just dont get why you would use the substitution to get tan²θ-∫tanθsec²θdθ when you have the solution to ∫tanθsec²θdθ
thats the only part i dont get
and on the second one it was x³ not xsquared
although your solution helps me begin to solve it myself im not sure if im doing it correctly because of the ³
It's integration by parts:
only, in this case it happens to be that:
and so, we end up with
For second one, taking the same approach again with partial fractions:
Last edited by luca-deltodesco (2008-11-30 08:52:23)
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luca-deltodesco thank you very much that helped alot
i now understand why you are a super member <3
luca-deltodesco thank you very much that helped alot
i now understand why you are a super member <3
which one in his/her profile says that he's a super member?
Actually I never watch Star Wars and not interested in it anyway, but I choose a Yoda card as my avatar in honor of our great friend bobbym who has passed away.
May his adventurous soul rest in peace at heaven.
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we have:
you could also have:
These are incorrect. All of the forms involving the natural logarithm for the answer must have absolute value
bars where the logarithm of the quantity is being taken of in these examples, not just parentheses.
This goes for the rest of your posts in this thread.
Last edited by greg1313 (2017-06-13 08:34:20)
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