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Hi, please check if I have made any mistake.
Determine if
contain a primitive on .Below is my working:
Since
has analytic domainwhere
Therefore,
does not has a primitive on .Thanks in advance.
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Hi, it seems correct, the only obscure part for me was the following:
Since
has analytic domain
But after looking at it for a couple of minutes it became clear. If you write the complex logarithm it is easier.
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Hi dannyv, thanks for the effort
By the way could you elaborate what do you mean by if I write the complex logarithm it is easier?
Thanks.
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coffeeking, as long as you are familiar with branch cuts, I'd say you don't need to show any more work than that.
But remember that log(z-1) has many analytic domains, depending on how you take your argument to be. It is true though that every single one of these domains does not include C \ {1}.
"In the real world, this would be a problem. But in mathematics, we can just define a place where this problem doesn't exist. So we'll go ahead and do that now..."
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Hi Ricky thanks for the info
I have to say that there are lots of helpful helper here thanks!
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