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#1 2009-07-13 19:07:55

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

A question about the matrix convention

(Summation is assumed)
I think its normally this


but my book defines it as

I found it weird it doesnt look consistent, if the first one is a matrix times a column vector, then the second one is a transpose matrix times a row vector?

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#2 2009-07-14 04:27:51

Ricky
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Registered: 2005-12-04
Posts: 3,791

Re: A question about the matrix convention

What book?


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#3 2009-07-14 17:03:06

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

Re: A question about the matrix convention

Ricky wrote:

What book?

Mathematics of Classical and Quantum physics by Fredrick W.Byron, Jr.  and Robert W.Fuller

Oh, I think I know what's going on, he defines


but still wanna know why

Last edited by Dragonshade (2009-07-14 17:13:38)

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#4 2009-07-14 18:12:42

Ricky
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Registered: 2005-12-04
Posts: 3,791

Re: A question about the matrix convention

The page in question is here.

By "x_j" what the author means is the vector (0, ..., 1, ..., 0) where the 1 is in the jth component.  This is of course relative to the basis, so the real vector (not written just as components) is:

Hopefully that makes sense.  Now multiplying this element by the matrix should reveal the vector:

But since we write this in terms of the basis {x_i}, this is really:

As the author claims.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#5 2009-07-14 20:18:49

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

Re: A question about the matrix convention

So this is just a definition. He wrote that vector in term of basis x_i with corresponding column(j) elements. So it could have been row(j) elements, but they are equivalent?

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#6 2009-07-15 02:44:40

Ricky
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Registered: 2005-12-04
Posts: 3,791

Re: A question about the matrix convention

I corrected a typo in my last line, the last term was x_j and it is now x_n.

This is not a definition, it's just using the standard definition of matrix multiplication on the vector (0, ..., 1, ..., 0).

So it could have been row(j) elements, but they are equivalent?

No, whenever doing matrix multiplication (i.e. applying a linear transformation), vectors are always column vectors.


"In the real world, this would be a problem.  But in mathematics, we can just define a place where this problem doesn't exist.  So we'll go ahead and do that now..."

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#7 2009-07-15 14:01:21

Dragonshade
Member
Registered: 2008-01-16
Posts: 147

Re: A question about the matrix convention

Ricky wrote:

I corrected a typo in my last line, the last term was x_j and it is now x_n.

This is not a definition, it's just using the standard definition of matrix multiplication on the vector (0, ..., 1, ..., 0).

So it could have been row(j) elements, but they are equivalent?

No, whenever doing matrix multiplication (i.e. applying a linear transformation), vectors are always column vectors.

oh, ok. Got it. later I saw the author used put the eigen vectors in columns instead of rows.  Thanks : )

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