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H(z)= -a for z>0, 1 for z <0, and 1/2 at z=0.
would this integral be written as:
If yes, then what is G(x) ? My book shows it's related to the error function but I cant figure it out. How would we represent the integral when H(z) is discontinuous at z=0 ?
P.S. 'a' is a real constant, nothing more.
Hi Hunter;
A question: what happened to the value of H(z) = 1/2 at 0 in f(x) ?
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
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