You are not logged in.
DESPERATE URGENT HELP NEEDED. PLEASE HELP WITH SOLUTION for this problem.
There is a 1 m cube wooden box placed up against a wall. A ladder measuring 4 m long is placed so it rests on the floor, touches the edge of the box and the top of it rests on the wall. How far up the wall is the top of the ladder?
Please find solution. Thanks.
Offline
Hi;
That is not exactly right the base of the triangle formed by the ladder and the wall is not 1m. That is the side of the cube. The base is > 1.
Look here to see what I mean.
http://www.stirlingsouth.com/richard/trig9.htm
Last edited by bobbym (2009-10-11 20:34:51)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Hi, thanks for the posts. Sadly, the first proposed solution doesn't appear to be correct. Tony, your posts did not give mea solution although I really appreciate the lovely CAD diagram. Would you or anyone else out there happen to have the solution? I would really like to know how to solve this seeamingly simple problem that has vexed me no end.
Cheers.
Offline
Hi bhow;
Who is Tony? The link was just meant to show that the solution offered might not be correct.
Last edited by bobbym (2009-10-14 18:33:03)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Is there even one real answer? :S
If we assume the height of the wall at which the ladder touches is y and the space between the base of the ladder and the end of the box is x, we could do the following.
So y would depend on what angle the ladder is placed against the wall, which would determine the value of x. I can't say that is right, just a guess.
Last edited by Nook (2009-10-14 18:32:45)
Offline
Hi;
The ladder is:
1.36219999266324453 m up the wall
3.760905629544160105 m from the wall
This forms a right triangle that just touches the cube.
1.36219999266324453^2 + 3.7609056329544160105^2 ≈ 16 = 4^2 m
Last edited by bobbym (2009-10-15 07:45:28)
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Instinctively the problem appears to have more than one solution, but this what I have...
We will divide the ladder into two parts the upper part is (4-x) and the lower part is x.
The distance from the top of the box to the top of the ladder is y.
Last edited by Fruityloop (2009-10-14 22:30:35)
Offline
Hi;
You do nice work, loop!
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline
Thanks for the compliment Bobbym.
One thing I find troubling about this problem is that the problem suggests that it's
impossible to rest a ladder against the upper-outer edge of a box and drag the ladder away from
the box along the ground while keeping contact with the box and wall.
It's mathematically impossible!
I guess it's true but it somehow doesn't 'seem' right.
Last edited by Fruityloop (2009-10-14 22:47:02)
Offline
Hi Fruityloop;
I was amazed thet there was any solution. The stipulation of touching the box made me think no way, but...
In mathematics, you don't understand things. You just get used to them.
If it ain't broke, fix it until it is.
Always satisfy the Prime Directive of getting the right answer above all else.
Offline