Tough equation to differentiate

BeachRum1962 · 2009-11-20 02:19:20

I am trying to differentiate the following equation:

B(t) = B*/(1+be^-at) that is be raised to -at. a & b are parameters. The correct answer is as follows:

dB(t)/dt = aB(t)[1-(B(t)/B*)]

Please help, I have been working hours using chain rule product rule, substituting, etc. but to no avail. Thanks.

soroban · 2009-11-20 03:46:21

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simplyjasper · 2009-11-20 03:56:17

I did mine through partial fractions and manage to get the result ...
You can try mine if you think you are more comfortable with partial fractions...

Solving For Partial Fractions, u will get

Using B(t):

Taking Common Factor:

Last edited by simplyjasper (2009-11-20 04:45:20)

BeachRum1962 · 2009-11-20 04:01:50

Many thanks and impressive work. Take that nap now

BeachRum1962 · 2009-11-20 04:22:14

Ok simplyjasper please post your method but I almost had it using soroban's method.

simplyjasper · 2009-11-20 04:45:55

BeachRum1962 wrote:

Ok simplyjasper please post your method but I almost had it using soroban's method.

Posted by editing my previous post

Math Is Fun Forum

#1 2009-11-20 02:19:20

Tough equation to differentiate

#2 2009-11-20 03:46:21

Re: Tough equation to differentiate

#3 2009-11-20 03:56:17

Re: Tough equation to differentiate

#4 2009-11-20 04:01:50

Re: Tough equation to differentiate

#5 2009-11-20 04:22:14

Re: Tough equation to differentiate

#6 2009-11-20 04:45:55

Re: Tough equation to differentiate

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